2. A uniform meter scale supported at the 40 cm mark is in equilibrium when a...
2. A uniform meter scale supported at the 40 cm mark is in equilibrium when a 50g mass is suspended at the 10 cm mark of the scale. Find the mass of the scale.
Homework Answers
here,
mass suspended , m1 = 50 g
let the mass of scale be m2
equating the torques about the hinge
m1 * g * (40 - 10) - m2 * g * ( 50 - 40) = 0
50 * 30 = m2 * 10
m2 = 150 g
the mass of scale is 150 g
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