Question

Write net ionic reaction neutralization sulfamic acid by sodium hydroxide solution then calculate the concentration of sodium hydroxide if 0.4082g of sulfamic acid reacts with 38.9mL of NaOH. Molar mass of sulfamic acid 97.1g/mol. Why is sulfamic acid used for estimation of NaOH concentration?

Answer 1

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O Complete balanced equation.

2H⁺ + SO₄^2- + 2 Na⁺ + 2OH^- → 2Na⁺ + SO₄^2- + 2H₂O Full ionic reaction

2H⁺ + 2OH^- → 2H₂O Netionic equation

N₁V₁=N₂V₂ This is the equation. Where N₁ is the normality of sulfuric acid ,N₂ is normality of NaOH,V₁ &V₂ are the volumes of sulfuric acid and NaOH.

N = gram equivalent weight / liters of solution (sulfuric acid made up of 100ml standard flask,so L=100)------>N₁

Equivalent weight means molecular weight by the valence, Equivalent weight of sulfuric acid is 97.1/2

V₁ is the volume of sulfuric acid taken in to the conical flask=20ml

((97.1/2)*100)*20 =N₂*38.9

Normality of NaOH IS 0.296