The combustion of pentane can be represented by the following equation:
__C5H12 (g) + __O2(g) → __CO2(g) + __H2O(g)
Balance the equation and answer the next three questions.
1. If 270. g of C5H12 and 970. g O2 react, which reactant is used up first? (enter pentane or oxygen)
2. What is the mass of carbon dioxide produced? (Give your answer to 3 sig figs.) grams
3. What is the mass of water produced?(Give your answer to 3 sig figs.) grams
Tries 0/10 |
The combustion of pentane can be represented by the following equation: __C5H12 (g) + __O2(g) →...
The combustion of propane can be represented by the following equation: __ C3H8 (g) + __O2(g) → __CO2(g) + __H2O(g) Balance the equation and answer the next three questions. If 257. g of C3H8 and 951. g O2 react, which reactant is used up first? (enter propane or oxygen) What is the mass of carbon dioxide produced? (Give your answer to 3 sig figs.) What is the mass of water produced?(Give your answer to 3 sig figs.) grams
How many moles of oxygen gas react with 0.100 mol of pentane, C5H12? __C5H12 (g) + __O2(g) ----> __CO2(g) + __H2O(g)
Assuming complete combustion, 500.g of pentane (C5H12) reacts with 1.00 kg of oxygen gas. 1. What is the limiting reagent? 2. What is the theoretical yield of water? 3. If 350. grams of water are produced, what is the percent yield?
Assuming complete combustion, 500.g of pentane (C5H12) reacts with 1.00 kg of oxygen gas. 1. What is the limiting reagent? 2. What is the theoretical yield of water? 3. If 350. grams of water are produced, what is the percent yield?
Heat Evolved During Combustion Consider the following reaction: 2 CO(g) + O2(g) 2 CO2(9) Use standard heats of formation from Zumdahl 'Chemical Principles' 8th ed. Appendix Four pp A19 - A21. How much heat is evolved when 1.071x101 moles of CO(9) is burned in excess oxygen. Answer to 4 sig figs. 1pts Submit Answer Tries 0/5 How much heat is evolved when 1.681x102 g of CO(g) is burned in excess oxygen. Answer to 4 sig figs. 1pts Submit Answer Tries...
Pentane (C5H12) burns in oxygen to produce carbon dioxide and water via the following reaction: C5H12(g)+8O2(g)) Δ⟶ 5CO2(g)+6H2O(g) Calculate the mass of CO2 that can be produced if the reaction of 36.5 g of pentane and sufficient oxygen has a 65.0 % yield.
Based on the following chemical equation: 4HCN + 5O2 -> 2N2 + 4CO2 + 2H2O Identify the limiting reactant and the mass of N2 produced when 100.0 g of HCN react with 100.0 g of O2. Enter the chemical formula of the limiting reactant. The reactant that is present in excess will be (enter the chemical formula): The mass of N2 produced will be g. (3 sig figs will be sufficient) QUESTION 17 Based on the following chemical equation: 4HCN 502...
Balance the equation and then determine the liters of Oxygen need for the complete combustion of 768g of benzene (C6H6) if the reaction is run at 23.5oC and 765mHg? 2 C6H6(l) + 15 O2(g) ⟶ 12 CO2(g) + 6 H2O(g) grams of products (3 sig figs no units):
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Pentane (C5H12) burn in oxygen to form carbon dioxide and water according to the following reaction. What is the coefficient for water in the balanced equation? C5H12(l) + ? O2(g) → ? CO2(g) + ? H2O(g) 2 4 5 6 8