Karl Pearson originally called the Chi Square test a?
A. parametrically challenged test
B. normal distribution test
C. "jolly good" test
D. goodness-of-fit
Solution :
Karl Pearson originally called the Chi Square test a goodness-of-fit .
Option D) is correct .
Karl Pearson originally called the Chi Square test a? A. parametrically challenged test B. normal distribution...
When we carry out a chi-square goodness-of-fit test for a normal distribution, the null hypothesis states that the population: a) does not have a normal distribution. b) has a normal distribution. c) has a chi-square distribution. d) does not have a chi-square distribution. e) has k − 3 degrees of freedom.
When we carry out a chi- square goodness-of-fit test for a normal distribution, the null hypothesis states that the population Does not have a normal distribution Has a normal distribution Has a chi-square distribution Does not have a chi-square distribution Has k-3 degrees of freedom
A chi-square test for goodness of fit is used to examine the distribution of individuals across three categories, and a chi-square test for independence is used to examine the distribution of individuals in a 2×3 matrix of categories. Which test has the larger value for df? a. The test for independence b. Both tests have the same df . c. The df value depends on the sizes of the samples that are used. d. The test for goodness of fit
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure that all of the expected cell frequencies are at least five. The sample is divided into 7 intervals. The second through the sixth intervals all have expected cell frequencies of at least five. The first and the last intervals have expected cell frequencies of 1.5 each. After adjusting the number of intervals, the degrees of freedom for the chi-square statistic is ____. 2, 3,5,...
a) true b) false 42. For a chi-square distributed random variable with 10 degrees of freedom and a level of sigpificanoe computed value of the test statistics is 16.857. This will lead us to reject the null hypothesis. a) true b) false 43. A chi-square goodness-of-fit test is always conducted as: a. a lower-tail test b. an upper-tail test d. either a lower tail or upper tail test e. a two-tail test 44. A left-tailed area in the chi-square distribution...
The test statistic for goodness of fit has a chi-square distribution with k - 1 degrees of freedom provided that the expected frequencies for all categories are a. 10 or more. b. k or more. c. 2k. d. 5 or more.
I know that the sum of square of normal random variables follow a chi-square distribution. But when I learn how to do a goodness-fit test I don't know why the ratio of (O-E)^2/E follows a chi-square. I tried to square root of it first so that I might get something looks like a normal, but my new question arises : why (O-E)/sqrt(E) follows a normal-distribution? I know from sampling distribution that if the sample is from the same distribution as...
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure that all of the expected cell frequencies are at least five. The sample is divided into 7 intervals. The second through the sixth intervals all have expected cell frequencies of at least five. The first and the last intervals have expected cell frequencies of 1.5 each. After adjusting the number of intervals, the degrees of freedom for the chi-square statistic is O 2 3...
Which of the statements are correct? A condition for using the chi-square goodness-of-fit test is that all expected counts must be at least two. A condition for using the chi-square goodness-of-fit test is the observations are based on a random sample. The chi-square goodness-of-fit test uses n − 5 degrees of freedom. A) I only B) II only C) I and II only D) II and III only E) I, II, and III
When Chi-square distribution is used as a test of independence, the number of degrees of freedom is related to both the number of rows and the number of columns in the contingency table. Select one: True False Question 2 Answer saved Points out of 1.000 Flag question Question text A goodness of fit test can be used to determine if membership in categories of one variable is different as a function of membership in the categories of a second variable...