Imagine that you are working at a lab station (at the Mountain Dew factory) with an ultra pure water sample. Unfortunately, your lab neighbor accidentally splashes a few small drops of HCl in your sample when you aren't looking. What is the new pH of your ultra pure water if the HCl concentration is 5.0×10−7M solution of HCl?
ultra pure water is neutral.
thus it has a pH of 7
but, accidentally there is HCl added ie 5.0 x 10^-7
since, HCl is a strong acid.. so dissociate completely to produce H+ ions.
thus H+ ions = 5.0 × 10^-7
and pure H2O has = 10^-7
thus total [H+] = 5× 10^-7. +. 10^-7
= 6 x 10^-7
pH = -log[H+]
= -log(6× 10^-7)
= 6.22
Imagine that you are working at a lab station (at the Mountain Dew factory) with an...
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