An electric heater is used to heat up 3.00× 102 kg of water from 10.0°C to 80.0°C in twenty minutes. Assuming that the heater is connected to a 120-V (rms) source and all electric power is used to heat the water, what is the resistance of the coil in the heater? The specific heat of water is 4186 J/(kg K).
An electric heater is used to heat up 3.00× 102 kg of water from 10.0°C to...
An electric heater is used to boil small amounts of water and consists of a 10-Ω coil that is immersed directly in the water. It operates from a 120-V socket. How much time is required for the heater to raise the temperature of 0.38 kg of water from 29 °C to the normal boiling point? Take the specific heat capacity of water to be 4186 J/(kg·C°).
A small electric immersion heater is used to heat 57 g of water for a cup of instant coffee. The heater is labeled "140 watts" (it converts electrical energy to thermal energy at this rate). Calculate the time required to bring all this water from 22°C to 100°C, ignoring any heat losses. (The specific heat of water is 4186 J/kg-K.) Number Units the tolerance is +/-2%
A small electric immersion heater is used to heat 57 g of water for a cup of instant coffee. The heater is labeled “190 watts” (it converts electrical energy to thermal energy at this rate). Calculate the time required to bring all this water from 24°C to 100°C, ignoring any heat losses. (The specific heat of water is 4186 J/kg·K.) How can I solve this problem?
An electric immersion heater has a power rating of 1800 W. If the heater is placed in a 1.2 kg of water at 25 °C, how many minutes will it take to bring the water to a boiling temperature? (Assume that there is no heat loss except to the water itself. cwater=4186 J/kg.°C)
An electric immersion heater has a power rating of 1200 W. If the heater is placed in a 1.6 kg of water at 15 °C, how many minutes will it take to bring the water to a boiling temperature? (Assume that there is no heat loss except to the water itself. cwater=4186 J/kg.°C)
A small immersion heater is rated at 375W. The specific heat of water is 4186 J/kg?C?. Estimate how long it will take to heat a cup of soup (assume this is 250 mL of water) from 15?C to 64?C. Ignore the heat loss to the surrounding environment.
How much heat must be removed from 456 g of water at 25.0 degree C to change it into ice at -10.0 degree C? The specific heat of ice is 2090 J/kg K. the latent heat of fusion of water is 33.5 times 10^4 J/Kg, and the specific heat of water is 4186 J/kg K.
A physics student uses a 115.00 V immersion heater to heat 330.00 grams of water for herbal tea. During the two minutes it takes the water to heat, the physics student becomes bored and decides to figure out the resistance of the heater. The student starts with the assumption that the water is initially at the temperature of the room Ti = 25.00°C and reaches Tf = 100.00°C.The specific heat of the water is c = 4180 J/(kg · °C)....
What is the heat capacity of a 20.2-kg block of ice? The specific heat capacity of ice is 2.10 kJ/kg K. kJ/K It takes 880 J to raise the temperature of 350 g of lead from 0°C to 20.0°C. What is the specific heat of lead? kJ/(kg K) A heating coil inside an electric kettle delivers 3.20 kW of electric power to the water in the kettle. How long will it take to raise the temperature of 0.390 kg of...
A small immersion heater is rated at 345W . The specific heat of water is 4186 J/kg?C?. Part A Estimate how long it will take to heat a cup of soup (assume this is 250 mL of water) from 18?C to 71?C. Ignore the heat loss to the surrounding environment.