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python3.x Write a function print_letter_count(word) that takes a string as a parameter and prints each unique...

python3.x

Write a function print_letter_count(word) that takes a string as a parameter and prints each unique character (in alphabetical order and lowercase) together with their frequency. For example: consider the following word:

Programming

The characters are: 1 x p, 2 x r, 1 x o, 2 x g, 1 x a, 2 x m, 1 x i and 1 x n. The output would be:

a: 1
g: 2
i: 1
m: 2
n: 1
o: 1
p: 1
r: 2

Note:

  • The parameter string may contain uppercase letters
  • The output is in alphabetical order.

For example:

Test Result 
print_letter_count('Programming')
 
a: 1
g: 2
i: 1
m: 2
n: 1
o: 1
p: 1
r: 2
 
print_letter_count('Combination')
 
a: 1
b: 1
c: 1
i: 2
m: 1
n: 2
o: 2
t: 1
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Answer #1

Hey here is answer to your question.

In case of any doubt comment below. if you liked the answer feel free to upvote this.

Explanation :- how it works is we take a string and we make a dict in python. then we loop over the string and check if its exist in dict then increase the counter.

def print_letter_count(string):
   string =string.lower()
   answer = {}
  
   for i in string:
   if i in answer:
   answer[i] += 1
   else:
   answer[i] = 1
   for i in sorted(answer.keys()):
      print(str(i) + " : "+str(answer[i]))


#print_letter_count('Programming')
print_letter_count('Combination')

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