design the following rectangular floor beam for a
building.
The beam has a simple span of 21ft. The uniform service load is 520lbs/ft live load. Consider the self-weight of the beam as dead load.
Assume f’c = 4,000 psi, fy = 60,000 psi, and #3 stirrups.
Required:
a) Conduct a free-beam design for the above conditions.
design the following rectangular floor beam for a building. The beam has a simple span of...
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load (DL) (self-weight included) and 2.47kip/ft live load (LL) on a span length of 18 ft. The beam is limited to be (due to architectural reasons) 10” wide with an overall depth of 20”. Use f’c= 3,000 psi and fy= 40,000psi. Design the longitudinal reinforcement (flexure design) and the web reinforcement (Stirrups).
Design a rectangular simple supported beam to carry service loads of 1.05 kips/ft of dead load (DL) (self-weight included) and 2.47kip/ft live load (LL) on a span length of 18 ft. The beam is limited to be (due to architectural reasons) 10” wide with an overall depth of 20”. Use f’c= 3,000 psi and fy=40,000psi. Design the longitudinal reinforcement (flexure design) and the web reinforcement (Stirrups).
A rectangular beam having b=16 in and d=26 in spans 28 ft face to face of simple supports. It is reinforced for flexure with 6#11 bars that continue uninterrupted to the ends of the span. It is to carry service dead load 2.0 kips/ft (including self weight) and service live load 3.6 kips/ft, both uniformly distributed along the span. Design the shear reinforcement using vertical U stirrups. Economize the spacing of stirrups in appropriate number of bands. Material strengths are...
2. A rectangular beam with b = 12 in., d = 17 in., and h = 20 in. spans 23 feet from simple supports. Each support is 12 inches wide (clear span between face of supports = 22 feet). The unfactored dead load (excluding self-weight) = 0.9 k/ft, and the unfactored live load = 1.25 k/ft. As = 6.0 in.2 . Material strengths are f’c = 3,500, fy = 60,000 psi. Shear reinforcement consists of #3 stirrups at 8 in....
A simply supported inverted T-beam has a clear span ln = 32 ft and is subjected to its own weight and the point loads P as shown. The point load P consists of a service dead load of 16 kips and a service live load of 28kips. Design #3 vertical stirrups for the beam (ignore any torsional effects). Assume d = 41.5 in., ƒc’ = 4,000 psi, and ƒy = 60,000 psi. 1. A simply supported inverted T-beam has a...
A rectangular beam having b-10 in. and d= 17.5 in. spans 15 ft face to face of simple supports. It is reinforced for flexure with three No. 9 (No. 29) bars that continue uninterrupted to the ends of the span. It is to carry service dead load D 1.27 kips/ft (including self-weight) and service live load L -3.70 kips/ft, both uniformly distributed along the span. Design the shear reinforcement, using No. 3 (No. 10) vertical U stirrups. The more approximate...
Concrete design Problem #1: Design a rectangular beam section, i.e. select b, d, h, and the required area of tension steel, A, at mid-span for a 22 ft-span simply supported beam that support its own weight, a superimposed service dead load of 1.25 kip/ft, and a uniform service live load of 2 kip/ft. Start by assuming the self-weight of the beam W-410 lbs/ft, b-0.7d, and use fc4500 psi and fy-60, 000 psi Note: Provide a detailed sketch for the final...
A rectangular beam that must carry a service live load of 2.47 kips/ft and a calculated dead load of 1.05 kips/ft on an 18 ft simple span is limited in cross section for architectural reasons to 10 in. width and 20 in. total depth. If fy=60,000 psi and fc′=4,000 psi, what steel area(s) must be provided. A rectangular beam that must carry a service live load of 2.47 kips/ft and a calculated dead load of 1.05 kips/ft on an 18...
Problem #2 (33%) Design the T-beam for the floor system shown below. The floor has a 4-in. slab suspoted by 22-ft-span-length beams cast monolithically with the slab. Beams are 8 ft- 0 in. on center and have a web width of 12 22 in.; fe' 3000 psi in. and a total depth and fy 60,000 psi. Service loads are 0.125- ksf live load and 0.200-ksf dead load. The given dead load does not include the weight of the floor system....
The T-beam shown in Figure 1 supports the un-factored dead load of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not include the self-weight of the beam. The material properties are as follows: fc’=3000 psi; fy=60,000 psi. Design the shear reinforcement (stirrups). Plot the stirrups distribution along the span of the beam. DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in