the average selling price of a smartphone purchased by a random sample of 46 customers was...
The average selling price of a smartphone purchased by a random sample of 43 customers was $315. Assume the population standard deviation was $34. a. Construct a 95% confidence interval to estimate the average selling price in the population with this sample. b. What is the margin of error for this interval? a. The 95% confidence interval has a lower limit of and an upper limit of. (Round to the nearest cent as needed.) b. The margin of error is....
find a. the 95% confidence interval has s lower limit of $____ and an upper limit of $_____ find b. what is the margin of error for this interval? 8.2. TU-1 Question Help Hor The average selling price of a smartphone purchased by a random sample of 31 customers was $299. Assume the population standard deviation was $32 a. Construct a 95% confidence interval to estimate the average selling price in the population with this sample. b. What is the...
1. A random sample of 82 customers, who visited a department store, spent an average of $71 at this store. Suppose the standard deviation of expenditures at this store is O = $19. What is the e 98% confidence interval for the population mean? 2. A sample of 25 elements produced a mean of 123.4 and a standard deviation of 18.32 Assuming that the population has a normal distribution, what is the 90% confidence interval for the population mean? 3....
Michelle is brought in by a provider to determine the number of times per day their customers interact with their smartphone. You take a random sample of 20 customers and find the mean average number of interactions to be 45 times per day with a sample standard deviation of 8. A. Construct a 95% confidence interval (to 2 decimal places) estimate for the population mean number of interactions. B. What is the margin of error for the confidence interval you...
5. A random sample of 625 customers of the restaurant xyz revealed the average monthly expenses in the amount of € 43.50 with a standard deviation of 19.20. a) Assuming that the dining expenses are normally distributed, construct a 95% confidence interval for the population mean expenses among xyz consumers( keep 2 decimals in your answer) b) How confident are you that the estimated 43.50 will be within 1.50 of the population mean? c) What would your margin of error...
A random sample of 49 cherry shop customers was taken. The sample’s mean amount of time these cus-tomers stayed in the shop was 30 minutes with a sample standard deviation of 10 minutes. Develop a 95% confidence interval estimate for the mean of the population by answering this a) What is the margin of error? b) What is the confidence interval? c) Interpret your answer
A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the customers in the sample stayed in the restaurant was 45 minutes with a standard deviation of 14 minutes. a. Compute the standard error of the mean. b. Construct a 99% confidence interval for the true average amount of time customers spent in the restaurant. c. With a .99 probability, how large of a sample would have to be taken to provide a...
3 Construct a 90% confidence interval for the following random sample of Lucas Barrett's golf scores for a particular golf course he played so that he can figure out his true (population) aver 95 92 95 99 92 84 95 94 95 86 (hint: Use T-distribution table. Formula Interval estimate of a population mean when stan age score for the dared deviation is unknown) 4 The auto industry relies heavily on 0% financing to entice customers to purchase cars. In...
In a random sample of 11 people, the mean driving distance to work was 25.2 miles and the standard deviation was 7.3 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Identify margin of error Construct a 95% confidence interval for the population mean (___,___)
In a random sample of 46 Denver neighborhoods, the crime rates per 1000 population were found to have a mean of 64.2 and a sample standard deviation of 27.9. Find a 95% confidence interval for the population mean crime rate of all Denver neighborhoods. Interpret the confidence interval in context of the problem and find all of the following x-bar std dev n Confidence Level Margin of Error Point Estimate Lower Limit Upper Limit Thank you!