Question

A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative...

A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 1.90 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 2600 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 4.79 V/m, (b) in the negative z direction and has a magnitude of 4.79 V/m, and (c) in the positive x direction and has a magnitude of 4.79 V/m?

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative...

    A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.09 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 2030 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 3.58 V/m, (b)...

  • A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative...

    A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 2.52 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1960 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 3.44 V/m, (b)...

  • A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative...

    A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.26 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1980 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.92 V/m, (b)...

  • A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative...

    A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.26 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1980 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.92 V/m, (b)...

  • A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative...

    A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 2.37 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 2550 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.33 V/m, (b)...

  • Chapter 28, Problem 010 A proton travels through uniform magnetic and electric fields. The magnetic field...

    Chapter 28, Problem 010 A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 2.76 mt. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1890 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude...

  • - Your answer is partially correct A proton travels through uniform magnetic and electric fields. The...

    - Your answer is partially correct A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.34 ml. At one Instant the velocity of the proton is in the positive y direction and has a magnitude of 2490 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has...

  • An electron travels through the uniform magnetic field of field strength B = (2.5 i +...

    An electron travels through the uniform magnetic field of field strength B = (2.5 i + 3.5 j ) mT and electric field of field strength 4.00 I V/M .   If the electron is moving with the velocity v= (1500 j + 2000 k)m/s. Calculate the net force acting on the electron in terms of unit vector notation.

  • A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x...

    A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x 107 m/s and experiences an acceleration of 1.50 x 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field. 1.11e-2 magnitude Apply the expression for the force on a charge moving through a magnetic field to find the field from the acceleration it produces. T direction - Need Help? Read It Master...

  • Problem 1: An electron travels through the uniform magnetic field of field strength B = (2.5...

    Problem 1: An electron travels through the uniform magnetic field of field strength B = (2.5 i +3.5i) mt and electric field of field strength 4.00 IV/M. If the electron is moving with the velocity v= (1500 j + 2000 k)m/s. Calculate the net force acting on the electron in terms of unit vector notation.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT