free energy of formation is the free energy calculated
when 1 mol product is formed from its constituent
elements in their standard state.Hence when balanced reaction
shows formation of 1 mole product from it elements
in standard state, ∆Grxn°= ∆Gf
In the given set
2 H2g+O2g→ 2 H2Og 2 H2g+O2g→2 H2Og ∆Grxn°=-457.1 kJ=-457.1
kJ/mol
Here 2 mol product is formed : hence ∆Grxn° not same as ∆Gf of
H2O
NO(g) + ½ O2(g) --> NO2 (g) ∆Grxn°=-35.4 kJ
Here product is formed from some other compound ,not
from constituent elements : hence ∆Grxn° not same as ∆Gf of NO2
Cs+O2g→CO2g ∆Grxn°=-394.4 kJ
Here 1 mol CO2 formed from its constituent elements
C and O2 ,both in their standard state .So for this
reaction
∆Grxn° = ∆Gf(CO2)
Answer : option A
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Like in thermochemistry, we define standard Gibbs energy of formation of compound Gf0 just like how...
In thermochemistry, we used Hess Law to determine ethanlpy change of unknown reaction from the known reactions. Same approach can be used to find the Gibbs energy change for a unknown reaction too. Complete the following problem using “Hess Law” approach. Find ∆Grxn° for the reaction: 3 Cs+4 H2g→ C3H8g Use the following reactions with known ΔG’s: C3H8g+5 O2g→3 CO2g+4 H2Og . ∆Grxn°=-2074 kJ Cs+O2g→CO2g ∆Grxn°=-394.4 kJ 2 H2g+O2g→2 H2Og ∆Grxn°=-457.1 kJ
the standard Gibbs energy of formation (in kJ-mol-) of the compound at 298 K
4. (a) Calculate the Gibbs Free Energy of formation for urea at 25°C. Given: The standard enthalpy of formation is -333.17 kJ mol and the standard entropy of formation is 136.093 J K mol". (b) is the formation of urea a spontaneous process under these conditions? Explain. (7 pts) J mol
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs free energy of formation values can be found in this table. 3H2(g) + Fe,0,($) 2Fe(s) + 3 H,0 () AGran kJ/mol
What is the Standard Molar Gibbs Free Energy of Reaction, DGorxn for the following reaction, given the Standard Molar DGof values for each substance? C3H8 (g) + 5 O2 (g) ® 3 CO2 (g) + 4 H2O (l) Substance DGof (kJ/mol) C3H8 (g) -23.4 CO2 (g) -394.4 H2O (l) -237.1
1. What is the AGº of the reaction below, given the standard Gibbs free energy of formations provided. CH,(g) + 20kg) 5C0g) + 2H,0g) Substance AG (kJ/mol) CH4(g) 50.8 CO2(g) 394.4 H2O(g) -228.57 a. -50.8 kJ/mol b. -751 kJ/mol c. +113 kJ/mol d. -115 kJ/mol e. -807 kJ/mol
4. [201 At 500 K, we have the data of standard enthalpy of formation and standard entropy of formation as follows: AH° (kJ/mol) AfSe (J/K mol) Substance HI (g 32.41 221.63 Н2 (g) 5.88 145.64 I2 (g) 69.75 279.94 One mole of H2 and one mole of I2 are placed in a vessel at 500 K. At this temperature only gases are present and the equilibrium of the following reaction is established. Н2 (9) + I, (9) 2HI (g) (1)...
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Refer to the AGⓇ values. 3 H2(g) + Fe, 0,(s) 2 Fe(s) + 3 H2O(g) AG" Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs free energy of formation values can be found in this table. C,H,(8) +4 C1,() 2 CCI, (1) + H2(g) AGE. kJ/mol
What is the standard Gibbs free energy for the transformation of diamond to graphite at 298 K? Cdiamond?Cgraphite Express your answer to three significant figures and include the appropriate units. Gibbs free energy is a measure of the spontaneity of a chemical reaction. It is the chemical potential for a reaction, which is minimized at equilibrium. It is defined as G=H?TS Elemental carbon usually exists in one of two forms: graphite or diamond. It is generally believed that diamonds last...
1. The simplest ammonia formation is from nitrogen and hydrogen. Consider the reversible reaction N2(g) + 3H2(g) → 2NH3(g) The standard enthaply and Gibbs free energy of formation one mole NH3 is ∆H◦ m = −46.11 kJ mol−1 and ∆G◦ m = −16.78 kJ mol−1 . (a) What is equilibrium constant at standard condition (25°C and 1 atm)? (b) What is equilibrium constant at 60°C and 1 atm? (c) What is the Gibbs free-energy change relative to that under standard...