The equilibrium constant, Kc, for the following reaction is 1.20×10-2 at 500 K. PCl5(g) PCl3(g) +...

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Question

The equilibrium constant, Kc, for the following reaction is 1.20×10-2 at 500 K. PCl5(g) PCl3(g) + Cl2(g)

Calculate the equilibrium concentrations of reactant and products when 0.287 moles of PCl5(g) are introduced into a 1.00 L vessel at 500 K. [

PCl5] = M [PCl3] = M [Cl2] = M

Answer 1

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