Q 14.17: The story of Archimedes is that he was asked to determine if a crown made for the king contained all the gold it was supposed to contain, or if some less dense (and less expensive) silver had been substituted. How could he do this? A He could submerge the crown in water, measure the volume of displaced water, and see if the volume corresponded to the volume of gold that had been provided. B He could melt the...
According to legend, the following challenge led Archimedes to the discovery of his famous principle: Hieron, king of Syracuse, was suspicious that a new crownthat he had received from the royal goldsmith was not pure gold, as claimed. Archimedes was ordered to determine whether the crown was in fact made of pure gold, with the condition that only a nondestructive test would be allowed. Rather than answer the problem in the politically most expedient way (or perhaps extract a bribe...
LEARN MORE REMARKS Because the density of gold Is 1.93 x 104 kg/m", the crown is elther hollow, made of an alloy, or both. Despite the mathematical complexity, it is certainly conceivable that this was the method that occurred to Archimedes. Conceptually, it's a matter of realizing (or guessing) that equal weights of gold and a silver-gold alloy would have different scale readings when immersed in water because their densities and hence their volumes are different, leading to differing buoyant...
Take the density of the crown to be rho_c. What is the ratio of the crown's apparent weight (in water) W_apparent to its actual weight W_actual? Express your answer in terms of the density of the crown rho_c and the density of water rho_w. Imagine that the apparent weight of the crown in water is W_apparent = 4.50 N, and the actual weight is W_actual = 5.00 N. Is the crown made of pure (100%) gold? The density of water...
Bonus-1 point) According to Vitruvius, a new crown in the shape of a laurel wreath had been made for King Hiero lII, and Archimedes was asked to determine whether it was of solid gold, or whether silver had been added by a dishonest goldsmith. Archimedes had to solve the problem without damaging the crown, so he could not melt it down. While taking a bath, he noticed that the level of the water rose as he got in. He realized...
Ch 13 HW Problem 13.36 4 of 10 PartA Constants Periodic Table Archimedes' principle can be used not only to determine the specific gravity of a solid using a known liquid; the reverse can be done as well. As an example, a 4.00-kg aluminum ball has an apparent mass of 2.50 kg when submerged in a particular liquid: calculate the density of the liquid. p-1010 kg/m3 Correct Part B Derive a formula for determining the density of a liquid using...
PHYS 111 Laboratory - Pre-lab #13 (ARCHIMEDES' PRINCIPLE) Student Name: Lab Day and Time: Due at the beginning of lab. All answers must be legibly handwritten for credit. Show all work. References: lab manual, textbook Ch. 13.1 -13.3. 1) (lab manual and Ch. 13.3) What is Archimedes' Principle? 2) (lab manual and Ch. 13.1) A cylinder of an unknown material has a mass mi = 0.0226 kg, a diameter d=0.0191 (remember this is two times the radius), and a height...
please answer all these questions Archimedes Principle - Upward Tension Additional Force As shown in the above figure, a solid object has a density of 1200 kg/m3 and a volume of 7.80x10^-5 m3. It is lowered on a string into water and completely submerged without touching the container. The density of water is 1000 kg/m3. Keep 3 decimal places in all answers. (Don't use scientific notations.) Without the string, would the solid object sink in water or float in water?...
A piece of aluminum has a density of 2700 kg/m3 and a mass of 0.775 kg. The aluminum is completely submerged in a container of oil with a density of 650 kg/m3 1 A) B) What is the magnitude of the buoyant force acting on the aluminum? What would the apparent weight of the aluminum be if it were instead completely submerged in water? opparent wecighf of
3. Archimedes' Principle states that the buoyant force on an object partially or fully submerged in a fluid is equal to the weight of the fluid that the object displaces. For an object of density po floating partly submerged in a fluid of density pf, the buoyant force is given by F P19 SA(y)dy, where g is the acceleration due to gravity and A(y) is the area of a typical cross-section of the object. The weight of the object is...