An elastic cord vibrates with afrequency of 3.0 Hz when a mass of 0.57 kg is hung from it. Whatwill its frequency be if only 0.39 kg hangs from it?
Hz
Since this elastic cord is a simple harmonic oscillator like aspring, we can use the equation for finding the period of a mass ona spring to answer this question:
Using this equation, we solve for the elastic cord's constant(k)
T= 2π√(m/k)
k(T/2π)2= m
k= m/[(T/2π)2]
Knowing that T=1/frequency
we can do the algebra, we to get k = 2.08 N*m
Using k we solve for 1/T to learn that thefrequency of the elastic cord when 0.39 kg hangs from it is.37 HZ.
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