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What is the strength of the electric field 9.4 cm from a small glass bead that has been charged to +2.4 nC?
E= ? in N/C
What is the direction of the electric field 9.4 cm from a small glass bead that has been charged to +2.4 nC?
Toward the bead or away from the bead?
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Answer #1

F = kq/r2

(8.99x109) * (2.4x10-9)/.0942 = 2441 N/C, away from the bead since it is a positive charge(field goes from positive tonegative)

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