displacement = 6.5 m
speed =√2as
a =F/m
u have not given figure u find out net force from figure and then find accelration
substitute in above formula u ll get answer
An object of mass 6.50 kg undergoes a displacement S= 11.5 m i + 5.5 m j while it is being acted on by a net force F = 5.9 N i -2.2 N j. a) How much work is done on the object by the net force? b) If the object above starts from rest, what is its speed after it has undergone the displacement described above?
The (non-conservative) force propelling a 1.10 x 103-kg car up a mountain road does 6.50 x 106 J of work on the car. The car starts from rest at sea level and has a speed of 20.0 m/s at an altitude of 1.60 x 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are non-conservative forces.
A 0.60 kg block rests on a frictionless horizontal countertop, where it is attached to a massless spring whose k-value equals 18.0 N/m. Let x be the displacement, where x = 0 is the equilibrium position and x > 0 when the spring is stretched. The block is pushed, and the spring compressed, until xi = −4.00 cm. It then is released from rest and undergoes simple harmonic motion. (a)What is the block's maximum speed (in m/s) after it is...
A SUU-kg block starts from rest at the top of a 30.00 incline and slides a distance of 2.10 m down the more (a) Find the magnitude of the acceleration of the block. m/s2 (b) Find the coefficient of kinetic friction between block and plane. (c) Find the friction force acting on the block. magnitude direction ---Select--- (d) Find the speed of the block after it has slid 2.10 m. m/s
A 3.50-kg block starts from rest at the top of a 30.0° incline and slides a distance of 1.90 m down the incline in 1.80 s (a) Find the magnitude of the acceleration of the block. m/s (b) Find the coefficient of kinetic friction between block and plane. (c) Find the friction force acting on the block. magnitude direction Select- (d) Find the speed of the block after it has slid 1.90 m m/s Need Help? tMasterTalk to a Tutor...
Can you please help me with this physics word problem? Please explain briefly about each step! The final answer is already given in dark letter at the end of the question! 3. H = 8m v = 1 1m/s block of mass m = 1.8 kg starts at rest on a rough inclined plane a height H-8m above the ground. It slides down the plane, across a frictionless horizontal floor, and then around a riction less loop-the-loop of radius R...
answer is ?left = 0.252 m⁄s2, ?right = 0. Please show your work, Thank you! it is held between a 025 kg A light spring with force constant 35 N/m is compressed by 8.0 cm as it is held between a 0.25 kg block on the left and a 0.50 kg block on the right. Both blocks and the spring are resting on a horizontal surface. When the blocks are simultaneously released from rest, find the acceleration with which each...
Steven carefully places a m 1.95 kg wooden block on a frictionless ramp so that the block begins to slide dawn the ramp from rest. The ramp makes an angle of 55.3° up from the horizontal. Which forces do nonzero work on the block as it slides down the ramp? Прагпн! friction gravity spring How much total work has been done on the block after it slides down along the ramp a distance of 1.93 m? total work done on...
A block of weight w = 25.0 N sits on a frictionless inclined plane, which makes an angle θ = 28.0 ∘ with respect to the horizontal. A force of magnitude F = 11.7 N , applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed. 1. The block moves up an incline with constant speed. What is the total work Wtotal done on the block by all forces as the block...
I really need some help with part a and part b. if you could also explain how you got to the answers that would be greatly appreciated!! thank you! GP-03. A block of mass 2.5 kg slides down a frictionless incline plane from rest as shown in figure below. At the bottom, it strikes another block of mass 7.0 kg, which is initially at rest. (a) find the velocity of the smaller block right after the collision, if the heavier...