Question

masteringphysics.com

A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 130 kg football players at a height of 1.20 m.If her piston is 19.0 cm in diameter, what is thediameter of the football players' piston?
2 0
Add a comment Improve this question Transcribed image text
Answer #1

Fcheerleader/ Areacheerpiston = Ffootball/ Areafootball piston

Fcheerleader= 57 kg

Ffootball= 4players(130 kg)=520 kg

Areacheer piston=πr2=π(.095m)2=.0283 (can add more decimal places if needed)

Areafootball piston= Ffootball x Areacheer piston/ Fcheerleader

= (520kg)(.0283m2)/(57kg)

= .258 m2

Area=πr2

radius=√(Area/π)

=√(.258/π)=.286 m

diameter=2radius=2(.286)=.572 m=57.2 cm

**note some rounding error may be present Xp **

answered by: Danah
Add a comment
Answer #2
A 54.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 130 kg football players at a height of 1.30 m. If her piston is 15.0 cm in diameter,what is the diameter of the football players' piston?

The pressure inside the hydraulic lift is the same everywhere.
Pressure = force ÷ area
Force = weight
Pressure = weight ÷ area

For the cheerleader,
Weight = 54 * 9.8 = 529.2 N
P = 529.2 ÷ (p * 0.15^2) = 23520 ÷ p

For the football players,
Weight = 4 * 130 * 9.8 = 5096 N
P = 5096 ÷ (p * r^2)

23520 ÷ p = 5096 ÷ (p * r^2)
Multiply both sides by p
23520 = 5096 ÷ r^2
r^2 = 5096 ÷ 23520
r = (5096 ÷ 23520)^0.5 = 0.465 m
Radius of football players' piston = 46.5 cm
answered by: Bree-Bree
Add a comment
Answer #3
A 54.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 130 kg football players at a height of 1.30 m. If her piston is 15.0 cm in diameter,what is the diameter of the football players' piston?

The pressure inside the hydraulic lift is the same everywhere.
Pressure = force ÷ area
Force = weight
Pressure = weight ÷ area

For the cheerleader,
Weight = 54 * 9.8 = 529.2 N
P = 529.2 ÷ (p * 0.15^2) = 23520 ÷ p

For the football players,
Weight = 4 * 130 * 9.8 = 5096 N
P = 5096 ÷ (p * r^2)

23520 ÷ p = 5096 ÷ (p * r^2)
Multiply both sides by p
23520 = 5096 ÷ r^2
r^2 = 5096 ÷ 23520
r = (5096 ÷ 23520)^0.5 = 0.465 m
Radius of football players' piston = 46.5 cm
answered by: 45
Add a comment
Know the answer?
Add Answer to:
masteringphysics.com
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Review Part A A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120...

    Review Part A A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m If her piston is 17.0 cm in diameter, what is the diameter of the football players' piston? Express your answer with the appropriate units. 106 cm Submit

  • A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players...

    A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 0.800 m Part A If her piston is 16.0 cm in diameter, what is the diameter of the football players' piston? Express your answer with the appropriate units. IA Value cm Submit Request Answer

  • Review Part A A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120...

    Review Part A A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m If her piston is 17.0 cm in diameter, what is the diameter of the football players' piston? Express your answer with the appropriate units. 49.3 cm Submit Incorrect; Try Again; 4 attempts remaining SWER 1: Deduction:-3% 0.49 m NSWER 2: Deduction:-3% 49.3 cm ANSWER 3: Deduction:-3% 87.4 cm ANSWER 4: Deduction:-3% 106 cm

  • The answer is E A 12,000-N car is raised using a hydraulic lift, which consists of...

    The answer is E A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil with a density of 800 kg/m^3 and capped at both ends with tight-fitting pistons. The wider arm of the U-tube has a radius of 18.0 cm and the narrower arm has a radius of 5.00 cm. The car rests on the piston on the wider arm of the U-tube. The pistons are initially at...

  • Question 2 - 70 Marks A hydraulic car lift system is shown schematically in Figure 1....

    Question 2 - 70 Marks A hydraulic car lift system is shown schematically in Figure 1. The system is being designed to lift a 1500 kg car via two pistons (driven pistons) located underneath the wheels of the car (distributing the weight of the car so that half is on each piston). The cylindrical pistons each have a diameter of 10cm. The hydraulic system will be driven by a person sitting (or standing) on the driving piston. The car weighs...

  • Consider the hydraulic jack represented beside. It is filled with mineral oil (a lubricating liquid). Assume...

    Consider the hydraulic jack represented beside. It is filled with mineral oil (a lubricating liquid). Assume that a person is able to push the left piston (F1) with a maximum force of 343 N. The diameter of the piston on the left is only 2 cm and that of the piston on the right much larger at 40 cm. • A) If the piston on the right is used to lift a car, what is the highest car weight (in...

  • 1-90 A hydraulic lift is to be used to lift a 1900-kg weight by putting a...

    1-90 A hydraulic lift is to be used to lift a 1900-kg weight by putting a weight of 25 kg on a piston with a diameter of 10 cm. Determine the diameter of the piston on which the weight is to be placed. eigh. 1900 ky 25 kg F:f 10 cm D2 FIGURE P1-90

  • A hydraulic lift has two connected pistons with cross-sectional areas 5 cm2 and 250 cm2. It...

    A hydraulic lift has two connected pistons with cross-sectional areas 5 cm2 and 250 cm2. It is filled with oil of density 670 kg/m3. 1. What mass must be placed on the small piston to support a car of mass 1200 kg at equal fluid levels? m = 24kg 2. With the lift in balance with equal fluid levels, a person of mass 70 kg gets into the car. What is the equilibrium height difference in the fluid levels in...

  • Pascal’s principle: What force must be exerted on the master cylinder of a hydraulic lift to...

    Pascal’s principle: What force must be exerted on the master cylinder of a hydraulic lift to support the weight of a 1800 kg car resting on the slave cylinder? The master cylinder has a 2.00 cm diameter and the slave has a 25.0 cm diameter. Pascal’s principle: A barber’s chair rests on a hydraulic piston 10 cm in diameter. The input side has a piston with cross-sectional area of 10 cm2 which is pumped on using a foot pedal. If...

  • shown in the figure below, a hydraulic system has two pistons of different diameter and uses...

    shown in the figure below, a hydraulic system has two pistons of different diameter and uses a liquid of density p 850 kg/m3. The smaller piston has a diameter of 4.3 cm anda mass of 1.6 kg and the larger piston a diameter of 14 cm and a mass of 2.7 kg. Determine h the height difference between the two pistons As

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT