solved a similar question already with different numbers.. i put the question and the answer.. hope it helps!! :) kindly rate a lifesaver :)
The position of a mass oscillating on a spring is given byx= (6.8cm)cos[2πt/(0.91s)].
(a) What is the frequency of this motion?ANSWER:
givenThe position of a mass oscillating on a spring isx= (6.8cm) cos[2πt/(0.91s)]--------(1)a)we knowx = Acos[2πt/T] -------(2)whereT = time periodand frequency f = 1/Tcomparing (1) &(2) we getf = 1 / 0.91s= 1.1Hzb)from the figure it is clear that the time taken (t) to be atthe position x = -6.8cm for the first time is equal to thetime taken between 6.8cm to -6.8cm that is T/2so, t = T/2=0.91s /2=0.455 sThe position of a mass oscillating on a spring is given by x = ( 3.6 cm)cos[2pi t/(0.67s)].A. What is the period of this motion?T=? sB. What is the first time the mass is at the position x = 0?t=? s
A mass is attached to a spring & is oscillating up & down. The position of the oscillating mass is given by... y=(3.2 cm)*Cos[2*3.14*t/(0.58 sec)]; where t is time. Determine (a) the period of this motion; (b) the first time the mass is at position y=0. Please show all work.
A mass rests on a frictionless surface and is attached to the end of a spring. The mass is pulled so that the spring is stretched... I would appreciate to have a detailed explanation for the last one. Thank you in advance. A mass rests on a frictionless surface and is attached to the end of a spring. The mass is pulled so that the spring Is stretched. The mass Is then released, and It starts oscillating back and forth...
the position of a mass that is oscillating on a spring is given by x = (0.20m) cos [(5.00s^-1)t]. what is the period of the motion? what is the amplitude of the motion? what is the spring constant? what is the total mechanical energy of the system?
The position of a mass oscillating on a spring is given by x=(5.4cm)cos[2πt/(0.62s)]. A. What is the frequency of this motion? B. When is the mass first at the position x=−5.4cm ?
13.6 The equation for the position as a function of time for an oscillating spring is given by x 15 cm cos 47at a) What is the frequency? b) If the mass on the spring is 400 g, what is the spring constant of the spring? c) What is the position at t-0.023 82 d) What is the position at rad 1 0.08 s
A mass of 0.24 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by 7. x()(0.46 m)cos (12 rad/s)r]. Determine the following. (a) Amplirude of oscillation for the oscillating mass. (b) Period of the oscillation for the oscillating mass. 523 (c) Force constant (spring constant) for the spring. (d) Position of the mass after it has been oscillating for one half a period. 1.Gon NG...
The position as a function of time of a mass at the end of a spring that is undergoing SHM is given by x(t)=Asin( ωt+θ ). At time t=0.00 seconds, the oscillating mass-spring system has a displacement x=2.83 cm and a velocity v= 3.25cm/s. It is oscillating with an angular frequency of 2.64 radians per second. Determine the constants A and θ .
In-Class Assignment 2. The figure shows a position-versus-time graph for an oscillating mass m = 0.5 kg. x (cm) 20 10 0 -10 -20 I(s) 4 a. Determine the period of the motion. b. Determnine the angular frecquemcy of the motion c. Determine the amplitude of the motion. d. Determine the phase constant of the motion. e. Determine the maximum speed of the mass. f. Determine the maximum acceleration of the mass. g. Determine the total energy of the system....
A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a stretched position. The position of the mass at any time is described by x = (6.4 cm)cos[2nt/(1.58 s)]. Determine the following. (a) period of the motion 1.58 S (b) frequency of the oscillations 0.633 Hz (c) first time the mass is at the position x = 0 S (d) first time the mass is at the...