Homework Answers
Note : i took Ka values from sapling . please check whether it is match with your value or not . if any wrong that is only with Ka values.
a)
1.2 M NaNO2
pKa of HNO2 = 3.25
pH = 7 + 1/2 (pKa + log C)
= 7 + 1/2 (3.25 + log 1.2)
pH = 8.66
b)
pKa of HOCl = 7.40
pH = 7 + 1/2 (pKa + log C)
= 7 + 1/2 (7.40 + log 1.2)
pH = 10.74
c)
pKa = 9.886
pH = 7 + 1/2 (pKa + log C)
= 7 + 1/2 (9.886 + log 1.2)
pH = 11.98
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