I need help with creating the following:
Hello
ANSWER:
Hello,
a) A t-test is used when you're looking at a numerical variable - for example, height - and then comparing the averages of two separate populations or groups (e.g., males and females).
b)
Requirements
Null Hypothesis
H0: u1 - u2 = 0, where u1 is the mean of first population and u2 the mean of the second.
Older | Diff (X - M) | Sq. Diff (X - M)2 |
45 | 0.5 | 0.25 |
38 | -6.5 | 42.25 |
52 | 7.5 | 56.25 |
48 | 3.5 | 12.25 |
25 | -19.5 | 380.25 |
39 | -5.5 | 30.25 |
51 | 6.5 | 42.25 |
46 | 1.5 | 2.25 |
55 | 10.5 | 110.25 |
46 | 1.5 | 2.25 |
M: 44.50 | SS: 678.50 |
Younger | Diff (X - M) | Sq. Diff (X - M)2 |
34 | 5.9 | 34.81 |
22 | -6.1 | 37.21 |
15 | -13.1 | 171.61 |
27 | -1.1 | 1.21 |
37 | 8.9 | 79.21 |
41 | 12.9 | 166.41 |
24 | -4.1 | 16.81 |
19 | -9.1 | 82.81 |
26 | -2.1 | 4.41 |
36 | 7.9 | 62.41 |
M: 28.10 | SS: 656.90 |
Difference Scores Calculations
Treatment 1
N1: 10
df1 = N - 1 = 10 - 1 = 9
M1: 44.5
SS1: 678.5
s21 =
SS1/(N - 1) = 678.5/(10-1) =
75.39
Treatment 2
N2: 10
df2 = N - 1 = 10 - 1 = 9
M2: 28.1
SS2: 656.9
s22 =
SS2/(N - 1) = 656.9/(10-1) =
72.99
T-value Calculation
s2p =
((df1/(df1 +
df2)) * s21) +
((df2/(df2 +
df2)) * s22) =
((9/18) * 75.39) + ((9/18) * 72.99) = 74.19
s2M1 =
s2p/N1
= 74.19/10 = 7.42
s2M2 =
s2p/N2
= 74.19/10 = 7.42
t = (M1 -
M2)/√(s2M1
+ s2M2) =
16.4/√14.84 = 4.26
The t-value is 4.25755. The p-value is .000474. The result is significant at p < .05.
Conclusion: there is significant diffreance between the younger and older.
e) the younger and older are two diffrent categories and to compare two indepndent variables we can use two sample t-test for the analysis.
thanks
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