Question

Be sure to answer all parts. Find the pH during the titration of 20.00 mL of 0.2400 mol/L butanoic acid, CHCH2CH2COOH (Ka -1.54 x 10-5), with 0.2400 mol/L NaOH solution after each addition of titrant: (a) 0 mL (b) 10.00 ml. pH= (c) 15.00 mL d) 19.00 mLpH- (e) 19.95 mL (1) 20.00 mL (g) 20.05 mL pH= (h) 25.00 mL pH = pH = pH = pH = pH =

Answer 1

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