BASED ON THE GIVEN DATA, WE CAN FINDTHE VALUES OF A1,A2,A3 USING NAIVE GAUSS ELIMINATION BY USING MATLAB CODE
MATLAB CADE :-
CLOSE ALL
CLEAL
CLC
a = [24 -2860 7.26*1e5;
-2860 7.26*1e5 -1.86472*1e8;
7.26*1e5 -1.86472*1e8 5.24357*1e10];
b = [1.057*1e-4;-1.04162*1e-2;2.56799];
a = inv(A)*b;
printf('a1 = %f\na2 = %f\na3 = %f\n\n', a);
deltaD = 12.363*integral(@(t)a(1)+a(2)*t+a(3)*t.^2,80,-108)
OUTPUTWILL BE AS BELOW
A1 = 0.000005
A2 = 0.000000
A3 = -0.000000
deltaD = -0.0116
The equation for the thermal expansion coefficient, α = ai + a2T+437', is obtained using regressi...
I thought that the coefficient of linear thermal expansion would be what is given already...please help. Now the friends use data obtained in the simulation to identify materials A-E. They calculate and record the value of α for each material and use the table below to identify it. (Hint: The simulation rounds some of the data to two-digit accuracy, so calculate all coefficients of linear thermal expansion using AT 50.) Material Steel Copper Brass and BronzeAluminum Lead a ((°C)1) 11...