Question

c) Add the missing values for HOCI] and (OCI-] to Table 2. Table 2. Characteristics of solutions of various amounts of hypochlorous acid, HOCI, dissolved in water to make 1.00 L of solution at 25 °C. H30+1 OCH Moles of HOCI added 0.00 0.30 0.75 1.00 [H3O [OH HOCI 1.0 x 10-71.0x 10-7 9.3× 10-5 1.1 × 10-10 1.5×10-4 6.8 × 10-11 1.7 x 10-4 5.9x 10-11 0.75 1.0 1.5 x 10-4 1.7 x 10-4 Based on information from Table 2, calculate the number of moles of HOCI(aq) present at equilibrium for each of the three acidic solutions. 8. a) b) Explain why the number of moles of HOCI added is equal to the number of moles of HOCI at equilibrium in spite of the fact that some of the HOCl reacts!

Answer 1

a) In the case of the addition of 0.3 moles of HOCl to 1 liter of solution, the concentrations of HCOl and OCl- are:

[HOCl] = 0.3 M

[OCl-] = 9.3x10 ^ -5 M

b) The concentration of HOCl in the equilibrium is practically the same, because the HCOl is a weak acid, this means that only a very small and negligible (for the calculations) part of the acid dissociates in the water and forms H3O + ions, but that small part makes a difference in pH of the solution.

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