Question

A linear triatomic molecule made of atoms with masses m1, m2, m3 has I = (1/M) (m1m2r122+m1m3r132...

A linear triatomic molecule made of atoms with masses m1, m2, m3 has

I = (1/M) (m1m2r122+m1m3r132+m2m3r232)

M is the total mass of the molecule

the lowest frequency of microwave transitions of 1H12C14N and 2H12C14N occur at 88631 and 72415 MHz, respectively.

Calculate the bond distance n HCN.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

s shouon belous: lowestg.ㆆ e@juenegtsons itrag os C. 37/0ms- Thes & toye> .B HUvニ 4し13,15,5ヅ似10 6 |BDCp-36207.SX106constontS as Shouon belouwt -зу -46 a n?STEP This step is dlone 二12x1D Na a mo given or muto Ror Tneatia Na N62*16 12323, 2구지Jo 123 bond length tsa Ja M= 28X10-3 Simi lar to the procedure o Ic 28 No 52 12 + 16 256 1 311omSTEP- kjeus, uwe hauetin ( 4a) 168 Y232-2,2 6 Χο-18m2 1o .S Put this va lot tn ① 千Solve fo>.o6A 116A 2-22

Add a comment
Know the answer?
Add Answer to:
A linear triatomic molecule made of atoms with masses m1, m2, m3 has I = (1/M) (m1m2r122+m1m3r132...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A linear triatomic molecule made of atoms with masses m1, m2, m3 has I = (1/M)...

    A linear triatomic molecule made of atoms with masses m1, m2, m3 has I = (1/M) (m1m2r122+m1m3r132+m2m3r232) M is the total mass of the molecule the lowest frequency of microwave transitions of 1H12C14N and 2H12C14N occur at 88631 and 72415 MHz, respectively. Calculate the bond distance n HCN.

  • As shown in the figure below, two masses m1 = 4.80 kg and m2 which has...

    As shown in the figure below, two masses m1 = 4.80 kg and m2 which has a mass 80.0% that of my, are attached to a cord of negligible mass which passes over a frictionless pulley also of negligible mass. If m1 and m2 start from rest, after they have each traveled a distance h = 1.10 m, use energy content to determine the following. m M (a) the speed (in m/s) v of the masses m/s (b) the magnitude...

  • As shown in (Figure 1), five balls (masses m1 = 2.20kg, m2 = 2.15kg, m3 =...

    As shown in (Figure 1), five balls (masses m1 = 2.20kg, m2 = 2.15kg, m3 = 2.11 kg , m4 = 2.05 kg , m5 = 2.00kg) hang from a crossbar. Each mass is supported by "5-lb test" fishing line which will break when its tension force exceeds 22.2 N ( = 5.00 lb). When this device is placed in an elevator, which accelerates upward, only the lines attached to the 2.05 kg and 2.00kg masses do not break. Within...

  • Two blocks m1 and m2 with masses 50 kg and 100 kg respectively are connected by...

    Two blocks m1 and m2 with masses 50 kg and 100 kg respectively are connected by a string over a pulley that is frictionless with negligible mass. The 50 kg block slides on a 37 degree incline that has a coefficient of kinetic friction of 0.25. This block is also attached to a wall at the base of the incline by an ideal spring that has a spring coefficient of 100 N/m. The system is released from rest with a...

  • Three boxes, with masses m1, m2, m3 (kg) are stacked vertically; the bottom box is in...

    Three boxes, with masses m1, m2, m3 (kg) are stacked vertically; the bottom box is in contact with a rough floor and the surfaces between each box are also rough. An external force Fext (N) acts on the bottom box at an angle of XX degrees relative to the horizontal, as a result of which all three masses accelerate together with an acceleration a (m/s^2). a) Identify the number of forces acting on each box, b) starting with the top...

  • The show system is orbiting counterclockwise around stationary point O, r=2.4 m m1=1.5kg, m2=1.8kg, m3=2.3kg Linear...

    The show system is orbiting counterclockwise around stationary point O, r=2.4 m m1=1.5kg, m2=1.8kg, m3=2.3kg Linear velocity is the same for each particle and it is 2.8m/s at the presented point of time Theta is 12 degrees overall velocity of the entire system as a single vector =? overall acceleration of the entire system as a single vector?=? total kinetic energy of this system=? mi ma м»

  • 1. Carbon nanotubes are large cylindrical molecules made up of a network of covalently bound carb...

    1. Carbon nanotubes are large cylindrical molecules made up of a network of covalently bound carbon atoms. The electrons in carbon nanotubes can be considered as particles in a one-dimensional box. For a nanotube of length 30 nm what is the probability of an electron being within 10 nm of the centre of nanotube if the electron is in the state n 3? a. b. What wavelength of light is needed to excite the electron from the n-2 to n...

  • (4) Thermodynamic data suggests that copper monohalides (CuX) should exist as polymers in the gas...

    (4) Thermodynamic data suggests that copper monohalides (CuX) should exist as polymers in the gas phaso However, scientists have successfully synthesized CuX monomers and characterized them using microwave spectroscopy For Cu Br the J-13 14,J-1415 and J-1516 transitions occurred at 84421.34 MHz, 90449.25 MHz and 96476.72 MHz, respectively. Assuming Cu Br behaves as a 3D rigid rotor, answer the following questions. Note: Absorption frequency (in units of Hz) of a rotational transition (aka peak position in a microwave spectrum) corresponding...

  • I need answers for #5 and #7 2) m m2 ma Now, three masses (m, =...

    I need answers for #5 and #7 2) m m2 ma Now, three masses (m, = 4.4 kg, m2 = 13.2 kg and mz = 8.8) hang from three identical springs in a motionless elevator. The springs all have the same spring constant given above. What is the magnitude of the force the bottom spring exerts on the lower mass? 86.24 N Submit + 3) What is the distance the middle spring is stretched from its equilibrium length? 79.85 cm...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT