How to solve this problem using R-studio?
To test whether there is a significant difference in three or more group means, we use ONE WAY ANOVA.
(a) ONE WAY ANOVA:
HYPOTHESIS:
The hypothesis is given by:
: The mean plant species richness for three different locations are the same.
: The mean plant species richness for at least two different locations differ.
LEVEL OF SIGNIFICANCE:
ONE WAY ANOVA R OUTPUT:
CONCLUSION:
Since the p-value is which is less than . Hence we reject null hypothesis at 5% level and conclude that the mean plant species richness for at least two different locations differ.
BOX PLOT:
From the box plot we can conclude that there is a significant difference in the mean species richness for different locations. It can also be observed that the mean species richness for pt lookout is the highest and 18 mile swamp is the lowest.
Since we have found that there is significant difference in species richness among different locations, we use "Tukey Pairwise comparison" to test among which locations does the species richness differs.
PAIRWISE COMPARISON:
CONCLUSION:
Since the p-value 0.0021 is less than 0.05, there is a statistically significant difference in mean species richness between the locations pt lookout and 18 mile swamp at 5% level of significance.
o The difference in mean species richness between the locations pt lookout and 18 mile swamp is 9.03 ( i.e.) the species richness of pt lookout is 9.03 units higher than 18 mile swamp. The 95% confidence interval is (3.503, 14.564) i.e. the difference in the mean species richness between locations pt lookout and 18 mile swamp may lie between 3.503 and 14.564.
17. To obtain a preliminary measure of plant species richness in various habitats m2 quadrats wer...
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