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An agronomist crossed two true breeding Guava plants. one parent is characterized by being Round,...

An agronomist crossed two true breeding Guava plants. one parent is characterized by being Round, terminal, violet and constricted, while the other expresses the contrasting phenotype of wrinkled, axial, white and full. Assume that the four pairs of contrasting traits are controlled by four genes (RTVC) with each located on a separate chromosome. In the F1 generation, only round, axial, violet and Full were expressed while in the F2 generation all possible combination of these traits were expressed ratios consistent with Mendelian's inheritance

1)Constitute all the possible phenotypic growth and their frequencies

2)What is the frequency of the guava plant that will exhibit the dominant trait in the first 3 loci?

3)what is the frequency of the guava plant that exhibited the dominant trait in only the second and fourth loci?

4)what is the frequency of guava plant that exhibited the dominant trait third locus only?

5)assuming you were given a bag containing 10,000,000 guava seed arising from the crossing,

5a)what proportion of the seeds will produce plant dorminant in all the loci

5b)what proportion of the seeds in (a) above will breed through for the four traits?

6)list all the test cross progenies of the f1 with their phenotypic ratios.

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Answer #1

If RRTTVVCC is crossed with rrttvvcc, F1 generation will have a genotype of RrTtVvCc with all the dominant genes expressed. Given that F1 expressed round, axial, violet and full, it can be concluded that
R - round; T - axial; V - violet; C - full.
r - wrinkled; t - terminal; v - white; c - constricted
That is the phenotypic ratio would be: RTVC = 100%

Parent 1
RTVC rTVC RtVC rtVC RTvC rTvC RtvC rtvC RTVc rTVc RtVc rtVc RTvc rTvc Rtvc rtvc
Parent 2 RTVC RRTTVVCC rRTTVVCC RRtTVVCC rRtTVVCC RRTTvVCC rRTTvVCC RRtTvVCC rRtTvVCC RRTTVVcC rRTTVVcC RRtTVVcC rRtTVVcC RRTTvVcC rRTTvVcC RRtTvVcC rRtTvVcC
rTVC RrTTVVCC rrTTVVCC RrtTVVCC rrtTVVCC RrTTvVCC rrTTvVCC RrtTvVCC rrtTvVCC RrTTVVcC rrTTVVcC RrtTVVcC rrtTVVcC RrTTvVcC rrTTvVcC RrtTvVcC rrtTvVcC
RtVC RRTtVVCC rRTtVVCC RRttVVCC rRttVVCC RRTtvVCC rRTtvVCC RRttvVCC rRttvVCC RRTtVVcC rRTtVVcC RRttVVcC rRttVVcC RRTtvVcC rRTtvVcC RRttvVcC rRttvVcC
rtVC RrTtVVCC rrTtVVCC RrttVVCC rrttVVCC RrTtvVCC rrTtvVCC RrttvVCC rrttvVCC RrTtVVcC rrTtVVcC RrttVVcC rrttVVcC RrTtvVcC rrTtvVcC RrttvVcC rrttvVcC
RTvC RRTTVvCC rRTTVvCC RRtTVvCC rRtTVvCC RRTTvvCC rRTTvvCC RRtTvvCC rRtTvvCC RRTTVvcC rRTTVvcC RRtTVvcC rRtTVvcC RRTTvvcC rRTTvvcC RRtTvvcC rRtTvvcC
rTvC RrTTVvCC rrTTVvCC RrtTVvCC rrtTVvCC RrTTvvCC rrTTvvCC RrtTvvCC rrtTvvCC RrTTVvcC rrTTVvcC RrtTVvcC rrtTVvcC RrTTvvcC rrTTvvcC RrtTvvcC rrtTvvcC
RtvC RRTtVvCC rRTtVvCC RRttVvCC rRttVvCC RRTtvvCC rRTtvvCC RRttvvCC rRttvvCC RRTtVvcC rRTtVvcC RRttVvcC rRttVvcC RRTtvvcC rRTtvvcC RRttvvcC rRttvvcC
rtvC RrTtVvCC rrTtVvCC RrttVvCC rrttVvCC RrTtvvCC rrTtvvCC RrttvvCC rrttvvCC RrTtVvcC rrTtVvcC RrttVvcC rrttVvcC RrTtvvcC rrTtvvcC RrttvvcC rrttvvcC
RTVc RRTTVVCc rRTTVVCc RRtTVVCc rRtTVVCc RRTTvVCc rRTTvVCc RRtTvVCc rRtTvVCc RRTTVVcc rRTTVVcc RRtTVVcc rRtTVVcc RRTTvVcc rRTTvVcc RRtTvVcc rRtTvVcc
rTVc RrTTVVCc rrTTVVCc RrtTVVCc rrtTVVCc RrTTvVCc rrTTvVCc RrtTvVCc rrtTvVCc RrTTVVcc rrTTVVcc RrtTVVcc rrtTVVcc RrTTvVcc rrTTvVcc RrtTvVcc rrtTvVcc
RtVc RRTtVVCc rRTtVVCc RRttVVCc rRttVVCc RRTtvVCc rRTtvVCc RRttvVCc rRttvVCc RRTtVVcc rRTtVVcc RRttVVcc rRttVVcc RRTtvVcc rRTtvVcc RRttvVcc rRttvVcc
rtVc RrTtVVCc rrTtVVCc RrttVVCc rrttVVCc RrTtvVCc rrTtvVCc RrttvVCc rrttvVCc RrTtVVcc rrTtVVcc RrttVVcc rrttVVcc RrTtvVcc rrTtvVcc RrttvVcc rrttvVcc
RTvc RRTTVvCc rRTTVvCc RRtTVvCc rRtTVvCc RRTTvvCc rRTTvvCc RRtTvvCc rRtTvvCc RRTTVvcc rRTTVvcc RRtTVvcc rRtTVvcc RRTTvvcc rRTTvvcc RRtTvvcc rRtTvvcc
rTvc RrTTVvCc rrTTVvCc RrtTVvCc rrtTVvCc RrTTvvCc rrTTvvCc RrtTvvCc rrtTvvCc RrTTVvcc rrTTVvcc RrtTVvcc rrtTVvcc RrTTvvcc rrTTvvcc RrtTvvcc rrtTvvcc
Rtvc RRTtVvCc rRTtVvCc RRttVvCc rRttVvCc RRTtvvCc rRTtvvCc RRttvvCc rRttvvCc RRTtVvcc rRTtVvcc RRttVvcc rRttVvcc RRTtvvcc rRTtvvcc RRttvvcc rRttvvcc
rtvc RrTtVvCc rrTtVvCc RrttVvCc rrttVvCc RrTtvvCc rrTtvvCc RrttvvCc rrttvvCc RrTtVvcc rrTtVvcc RrttVvcc rrttVvcc RrTtvvcc rrTtvvcc Rrttvvcc rrttvvcc
Genotype
RrTtVvCc 6.25%
rrTtVvCc 3.13%
RrttVvCc 3.13%
RrTtvvCc 3.13%
RrTtVvcc 3.13%
RrTtVvCC 3.13%
RrTtVVCc 3.13%
RrTTVvCc 3.13%
RRTtVvCc 3.13%
rrttVvCc 1.56%
rrTtvvCc 1.56%
rrTtVvcc 1.56%
rrTtVvCC 1.56%
rrTtVVCc 1.56%
rrTTVvCc 1.56%
RrttvvCc 1.56%
RrttVvcc 1.56%
RrttVvCC 1.56%
RrttVVCc 1.56%
RrTtvvcc 1.56%
RrTtvvCC 1.56%
RrTtVVcc 1.56%
RrTtVVCC 1.56%
RrTTvvCc 1.56%
RrTTVvcc 1.56%
RrTTVvCC 1.56%
RrTTVVCc 1.56%
RRttVvCc 1.56%
RRTtvvCc 1.56%
RRTtVvcc 1.56%
RRTtVvCC 1.56%
RRTtVVCc 1.56%
RRTTVvCc 1.56%
rrttvvCc 0.78%
rrttVvcc 0.78%
rrttVvCC 0.78%
rrttVVCc 0.78%
rrTtvvcc 0.78%
rrTtvvCC 0.78%
rrTtVVcc 0.78%
rrTtVVCC 0.78%
rrTTvvCc 0.78%
rrTTVvcc 0.78%
rrTTVvCC 0.78%
rrTTVVCc 0.78%
Rrttvvcc 0.78%
RrttvvCC 0.78%
RrttVVcc 0.78%
RrttVVCC 0.78%
RrTTvvcc 0.78%
RrTTvvCC 0.78%
RrTTVVcc 0.78%
RrTTVVCC 0.78%
RRttvvCc 0.78%
RRttVvcc 0.78%
RRttVvCC 0.78%
RRttVVCc 0.78%
RRTtvvcc 0.78%
RRTtvvCC 0.78%
RRTtVVcc 0.78%
RRTtVVCC 0.78%
RRTTvvCc 0.78%
RRTTVvcc 0.78%
RRTTVvCC 0.78%
RRTTVVCc 0.78%
rrttvvcc 0.39%
rrttvvCC 0.39%
rrttVVcc 0.39%
rrttVVCC 0.39%
rrTTvvcc 0.39%
rrTTvvCC 0.39%
rrTTVVcc 0.39%
rrTTVVCC 0.39%
RRttvvcc 0.39%
RRttvvCC 0.39%
RRttVVcc 0.39%
RRttVVCC 0.39%
RRTTvvcc 0.39%
RRTTvvCC 0.39%
RRTTVVcc 0.39%
RRTTVVCC 0.39%

1. Phenotype ratio is 1:4:6:4:1

Phenotype
RTVC 31.64%
RTVc 10.55%
RTvC 10.55%
RtVC 10.55%
rTVC 10.55%
RTvc 3.52%
RtVc 3.52%
RtvC 3.52%
rTVc 3.52%
rTvC 3.52%
rtVC 3.52%
Rtvc 1.17%
rTvc 1.17%
rtVc 1.17%
rtvC 1.17%
rtvc 0.39%

2. The dominant trait in the first three loci will be exhibited by 42.19% of the guavas [RTVC - 31.64% + RTVc - 10.55%]

3. The dominant trait exhibited only in the second and fourth loci will be 3.52% [rTvC]

4. The dominant trait exhibited only in the fourth locus will be 1.17% [rtVc]

5. a) 31.64% exhibit the dominant trait in all the loci. Therefore, the proportion of seeds in 10,000,000 will be
10,000,000*0.3164 = 3164000

b) All of the seeds will exhibit the four traits

6. The test is done between the recessive parent and the F1, in this case.

Therefore cross would be rrttvvcc X RrTtVvCc.

Genotype
rrttvvcc 6.25%
rrttvvCc 6.25%
rrttVvcc 6.25%
rrttVvCc 6.25%
rrTtvvcc 6.25%
rrTtvvCc 6.25%
rrTtVvcc 6.25%
rrTtVvCc 6.25%
Rrttvvcc 6.25%
RrttvvCc 6.25%
RrttVvcc 6.25%
RrttVvCc 6.25%
RrTtvvcc 6.25%
RrTtvvCc 6.25%
RrTtVvcc 6.25%
RrTtVvCc 6.25%
Phenotype
RTVC 6.25%
RTVc 6.25%
RTvC 6.25%
RTvc 6.25%
RtVC 6.25%
RtVc 6.25%
RtvC 6.25%
Rtvc 6.25%
rTVC 6.25%
rTVc 6.25%
rTvC 6.25%
rTvc 6.25%
rtVC 6.25%
rtVc 6.25%
rtvC 6.25%
rtvc 6.25%
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