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1. Determine the support reactions for girders B-1, B-2, B-3 and G-2. Live load- 75 psf, Dead loa...
1. For the given framing plan, first identify all unique beams and columns. After that, find out the final load tra...
1. For the given framing plan, first identify all unique beams and columns. After that, find out the final load transferred on each beam and girder. Finally draw load diagrams for all beams and girders, and determine the support reactions. 50 ft 50 ft 50 ft 25 ft I(2 B1 25 ft 3 1 25 ft 4 25 ft A B D Use: Live load 110 PSF ead load excluding weight of the slab Thickness of concrete slab = 5...
2) Consider the arrangement of beams and girders that are used to support a 5 in...
2) Consider the arrangement of beams and girders that are used to support a 5 in reinforced concrete floor for a small industrial building as shown in Figure 2. Design the beams and girders assuming that they are simply supported. Assume full lateral support of the compression flange and a live load of 80 psf. Concrete weight is 150 lb/ft3. (5 pts) Note : Floor continues on all sides Column Girder Ronen Beam ? 3 at 8 ft24 ft Figure...
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100...
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy- 50 ksi 35 ft 15 ft Wu 35 ft
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy- 50 ksi 35 ft 15 ft Wu 35 ft
show work please!! 1. For the given framing plan, first identify all unique beams and columns....
show work please!!
1. For the given framing plan, first identify all unique beams and columns. After that, find out the final load transferred on each beam and girder. Finally draw load diagrams for all beams and girders, and determine the support reactions (70 Points) 50 ft 50 ft 50 ft 25 ft 25 ft 0 25 ft 25 ft Use Live load 110 PSF . Dead load excluding weight of the slab 15 PSF .Thickness of concrete slab 6...
please solve it manually and using ETABS. please solve it manually and using ETABS. 1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 p...
please solve it manually and using ETABS.
please solve it manually and using ETABS.
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy 50 ksi 35 ft 15 ft Wu 35 ft
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy 50...
Determine the beam and column reactions knowing that: • Live load (load on the deck): 80...
Determine the beam and column reactions knowing that: • Live load (load on the deck): 80 psf • Dead load (deck weight): 10psf Self-weight of beams: 15 pif
Using the Letter R so Dead load is 160 and Live load is 50
Using the Letter R so Dead load is 160 and Live load is
50
by 120 floor Design Problem: 150 girders Floor System: oor (Design for Bending onl nding only.ust beams and 120'x 150', Columns on a 30 Grid 1) 2) Girders span from Column to column in the 150 foot direction 3) Beams span between girders 4) Concrete floor spans across beams Loading: See table on following page Elements/Materials: 1) Beams: S-Shape a. Use same beam throughout b. No...
The floor system shown has a dead load that includes: Floor tile and bedding 17 psf...
The floor system shown has a dead load that includes: Floor tile and bedding 17 psf 2VLI20 (2" deep metal deck with 42" of concrete on top) Mechanical ducts = 4 psf Electrical 1 psf Gypsum board ceiling 3 psf Beam self-weight is given by its name (ie. W16x26 is 26 plf) Girder self-weight is given by its name (ie. W30x90 is 90 plf) The floor live load is 150 psf. 45 psf 1. Determine the end reactions for Beams...
1. For the building shown below, calculate the dead load, reduced live load, and maximum design...
1. For the building shown below, calculate the dead load, reduced live load, and maximum design load per IBC 2012, LRFD load combinations. Beam loads should be in plf, column loads should be in kips. [To be done by hand.] Note: It is acceptable check only equations 16-1 and 16-2 of IBC 2012. a. Beam I b. Веam II olumn A/3-supporting 1 story d. Column B/2- supporting 1 story C e. Column B/2-supporting 4 stories Given loading: Dead Load 60...
1. For the given framing plan, first identify all unique beams and columns. After that, find out the final load transferred on each beam and girder. Finally draw load diagrams for all beams and girders, and determine the support reactions. 50 ft 50 ft 50 ft 25 ft I(2 B1 25 ft 3 1 25 ft 4 25 ft A B D Use: Live load 110 PSF ead load excluding weight of the slab Thickness of concrete slab = 5...
2) Consider the arrangement of beams and girders that are used to support a 5 in reinforced concrete floor for a small industrial building as shown in Figure 2. Design the beams and girders assuming that they are simply supported. Assume full lateral support of the compression flange and a live load of 80 psf. Concrete weight is 150 lb/ft3. (5 pts) Note : Floor continues on all sides Column Girder Ronen Beam ? 3 at 8 ft24 ft Figure...
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy- 50 ksi 35 ft 15 ft Wu 35 ft
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy- 50 ksi 35 ft 15 ft Wu 35 ft
show work please!!
1. For the given framing plan, first identify all unique beams and columns. After that, find out the final load transferred on each beam and girder. Finally draw load diagrams for all beams and girders, and determine the support reactions (70 Points) 50 ft 50 ft 50 ft 25 ft 25 ft 0 25 ft 25 ft Use Live load 110 PSF . Dead load excluding weight of the slab 15 PSF .Thickness of concrete slab 6...
please solve it manually and using ETABS.
please solve it manually and using ETABS.
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy 50 ksi 35 ft 15 ft Wu 35 ft
1.) Select the lightest W beam to support the following loads 4 in. concrete slab 15 ft 40 psf dead load 15 ft 100 psf live load Fy 50...
Determine the beam and column reactions knowing that: • Live load (load on the deck): 80 psf • Dead load (deck weight): 10psf Self-weight of beams: 15 pif
Using the Letter R so Dead load is 160 and Live load is
50
by 120 floor Design Problem: 150 girders Floor System: oor (Design for Bending onl nding only.ust beams and 120'x 150', Columns on a 30 Grid 1) 2) Girders span from Column to column in the 150 foot direction 3) Beams span between girders 4) Concrete floor spans across beams Loading: See table on following page Elements/Materials: 1) Beams: S-Shape a. Use same beam throughout b. No...
The floor system shown has a dead load that includes: Floor tile and bedding 17 psf 2VLI20 (2" deep metal deck with 42" of concrete on top) Mechanical ducts = 4 psf Electrical 1 psf Gypsum board ceiling 3 psf Beam self-weight is given by its name (ie. W16x26 is 26 plf) Girder self-weight is given by its name (ie. W30x90 is 90 plf) The floor live load is 150 psf. 45 psf 1. Determine the end reactions for Beams...
1. For the building shown below, calculate the dead load, reduced live load, and maximum design load per IBC 2012, LRFD load combinations. Beam loads should be in plf, column loads should be in kips. [To be done by hand.] Note: It is acceptable check only equations 16-1 and 16-2 of IBC 2012. a. Beam I b. Веam II olumn A/3-supporting 1 story d. Column B/2- supporting 1 story C e. Column B/2-supporting 4 stories Given loading: Dead Load 60...
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