a) The Matlab code is given by
clear all
clc
s=tf('s');
G=4/(s*(s+2))
C=((417*s)/10 + 183897/1000)/(s + 92/5)
figure(1)
bode(G)
figure(2)
bode(C)
figure(3)
bode(G*C)
The command window will show
G =
4
---------
s^2 + 2 s
Continuous-time transfer function.
C =
417 s + 1839
------------
10 s + 184
Continuous-time transfer function.
Bode plot for plant G(s) is
Bode plot for controller C(s)
Bode plot for compensated plant C(s)*G(s)
b) The Matlab code is given by
clc
clear all
close all
syms s T z
c=41.7*(s+4.41)/(s+18.4);
subs(41.7*(s+4.41)/(s+18.4),s,(2*(z - 1))/(T*(z + 1)))
%Bilinear
subs(41.7*(s+4.41)/(s+18.4),s,(z-1)/T) %Eular
subs(41.7*(s+4.41)/(s+18.4),s,((2/T)*(z-1))/(z+1))%Tustin
Command window will show the following answers
Bilenear C(s)=
((417*(2*z - 2))/(10*T*(z + 1)) + 183897/1000)/((2*z - 2)/(T*(z + 1)) + 92/5)
Eular C(s)=
((417*(z - 1))/(10*T) + 183897/1000)/((z - 1)/T + 92/5)
Tustin C(s)=
((417*(z - 1))/(5*T*(z + 1)) + 183897/1000)/((2*(z - 1))/(T*(z + 1)) + 92/5)
Again the same is done
-2IH yes, what is K ? 2. (25pts)Given a continuous control system in the following Sgure, the pla...
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