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An important concern in the study of heat transfer is to determine the steady-state temperature distribution of a plate when

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Answer #1

Going as per the instructions, the equTion for the temperature at each nodes will be

1025 + B+ D

25 +30 +A+C B=

C = \frac{35 + 30 + B + D}{4}

35 + 10 A+C

On simplifying the eqn becomes

4A - B- D-35

4B-A-C=55

4C-B-D = 65

4D-A-C 45

Here we have 4 sets of equations and 4 unknown variables.

This can be solved using the matrix method,

4 -1 0 -1 A = 35

-1 4 -1 0 B = 55

0 -1 4 -1 C = 65

-1 0 -1 4 D = 45

This is of the form

AX = B

So to find X we need inverse of A

Were A is

4 1 0 1 1 41 0 0 1 4-1 1 0 4

So that X = B.A^{-1}

Here the inverse of the matrix is

7/24 1/12 1/24 1/12 1/12 7/24 1/12 1/24 1/24 1/12 7/24 1/12 1/12 1/24 1/12 | 7/24

To get the matrix X we multiply the inverse of A with matrix B

So we get, the matrix X as

85/4

105/4

115/4

95/4

So the temperature of four points are

A = 21.25

B = 26.25

C = 28.75

D = 23.75

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