Question 2: For the reinforced concrete structural plan shown. It is required to calculate the de...
Question 2: For the reinforced concrete structural plan shown. It is required to calculate the design working and ultimate loads for the marked beams B1, B2 and B3. Assume that Live loads; LL-3 kN/m2, Thickness of the slab=0.12 m, flooring cover = 1.5 kN/m2. fc 35 MPa, f 420 MPa 8 8 2 250B2 8 8 5 5 5 2
Question 2: For the reinforced concrete structural plan shown. It is required to calculate the design working and ultimate loads...
Design reinforcement for continuous edges of an inner two way slab of size 6.4 m 8 m. 1 Ultimate loads on slab are 6 KN/m' & 8 KN/m2 for DL and LL respectively fc -25MPa fy 420 MPa
Design reinforcement for continuous edges of an inner two way slab of size 6.4 m 8 m. 1 Ultimate loads on slab are 6 KN/m' & 8 KN/m2 for DL and LL respectively fc -25MPa fy 420 MPa
REINFORCED CONCRETE DESIGN CLASS PROJECT The structural floor plan of a three-story (ground floor, two suspended floors, and a roof office building is shown on the next page. The floor includes one and two way solid slabs. The new building will be located in Sharjah, UAE. The floor systems consist of one-way and two-way solid slabs supported by beams running in both directions as shown in the floor plan. The design loads for the floor (in addition to the self-weight)...
simply supported reinforced concrete beam of rectangular section is hung on the left end by a 400mm square post working in tension, as shown in the figure below. The beam supports a uniform dead load (DL) gf 100 KN/m (excluding its own weight) and upiform live load LL) of 40KN/m. The beam is reinforced with 025 longitudinal rebars with 40mm cleat cover to the stirrups. Material properties: fy 420 MPa, fe 25 MPa. Beam dimension b 400mm and h 600mm....
It is required to design a reinforced concrete one-slab used as
a floor of a domestic building. The floor is to support a live load
of 4 kPa. Take Ln = 5m, f'c=25MPa,
fsy = 500 MPa, and clear cover to reinforcement is 25
mm.
Question-2 It is required to design a reinforced concrete one-slab used as a floor of a domestic building. The floor is to support a live load of 4 kPa. Take L. = 5 m, fc'...
RENFORCEMENT CONCRETE DESIGN (ACI-Code 2019).
Reinforced Concrete Design Example 1: Using the ACI-Code approximate structural analysis, design for a warehouse, a continuous one-way solid slab supported on beams 4.0 m apart as shown in Figure. Assume that the beam webs are 30 cm wide. The dead load is 3 kN/m² in addition to the own weight of the slab, and the live load is 3 kN/m². Use fcº=28MPa, fy= 420MPa 8.0 m 4.0 m 4.0 m 4.0 m
The reinforced concrete beam shown in Figure-2 is to be subjected to the following uniformly distributed loads over the entire length: DL = 14 kn/m (including self-weight) and LL = 20kN/m, fc = 32 MPa. For architectural reasons the beam width is set at 500 mm. Determine the effective depth required if ku = 0.25 for the section of maximum positive bending moment. Then design the reinforcement required. zin Figure-2
Question .2 A structural system that supports a reading room is being considered for a new library. The floor consists of a 125 mm thick slab of normal density reinforced concrete supported by steel beams and columns. The steel beams weigh 90 kg/m while the steel columns weigh 150 kg/m. In addition to self weight, dead loads must include a 1.0 kPa allotment for partitions and a 0.5 kPa allotment for flooring/ceiling/services. Determine, (a) the specified (i.e. unfactored) distributed load...
Task 1: (50 Marks) Cross section of a reinforced concrete beam is shown in Figure 1. The following shear forces have been calculated due to Dead Load and Live Load at the support: VDL = 150 kN, ViL = 200 kN. Design the shear reinforcement for the ultimate shear force. Use No. 10 bars for shear reinforcement Assume "fe, = 28 MPa, fyt-420 MPa, b = 300 mm, d = 750 mm, h = 800 mm Figure 1. Beam cross-section
Problem 1 Reinforced Concrete T-Flanged Sections (50 pts.) You are required to analyze and design the propped cantilever t-section from HM 4 but for shear only. Draw shear V and moment M diagrams for uniformly distributed load throughout the 30ft span and equally concentrated loads at 10ft and 30ft. Recall that the connection at the left joint N1 is fixed. The connection at 20ft N3 is a roller. The right end node N2 is a free end. Use a concrete...