Tofind the point. --(4/-15? +18s + 5)-0 -1.68 ±0.6i s =-0.39 5) Choose a test point near s 2 + j....
Problem (4): Sketch the root locus plot for a system, whose transfer function are given by 10 K (s2 +3 s+7) the complex poles. G(s) (s +3) i) Determine the joo -axis crossing, breakaway point and the angle of departure from (i) Determine the value of the gain for which the closed loop system will have a pole at (-10)
Problem (4): Sketch the root locus plot for a system, whose transfer function are given by 10 K (s2 +3...
9. (10 pts) Choose your own root locus adventure. (a) First, choose one open-loop transfer function (circle it): a) G(s)H(s) = (8+3)(8 +1) 2 - 4s +5 5 b) G(s)H(s) = (5+3)(8 + 4) (92 +2s + 2) (b) Second, sketch the general shape/path of the root locus plot. Do not calculate details of the root locus plot yet. I.E. complete procedure steps 1-3. (c) Finally, complete one of the following circle your choice): i. Calculate the angle of departure...
023 (part 1 of 2) 10.0 point A merry-go-round rotates at the rate of 0.39 rev/s with an 84 kg man standing at a point 1.4:11 from the ax of rotation : What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 71 kg cylinder of radius of 1.4 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change...
Problem 3: (30) Consider the following systen where K is a proportional gain (K>0). s-2 (a) Sketch the root locus using the below procedures. (1) find poles and zeros and locate on complex domain (2) find number of branches (3) find asymptotes including centroid and angles of asymptotes (4) intersection at imaginary axis (5) find the angle of departure (6) draw the root migration (b) Find the range of K for which the feedback system is asymptotically stable.
Problem 3:...
Problem 4 Suppose we have the system shown below operating at 15% overshoot. G(s)- (G) (s +2)%s +5%s+7) Use time domain techniques to design a compensator (and find K) so the appropriate static error constant is 20 without appreciably changing the dominant poles of the uncompensated system. There can be no zero pole cancellations. Do not change the dominant poles of the system.
Problem 4 Suppose we have the system shown below operating at 15% overshoot. G(s)- (G) (s +2)%s...
The economy in Figure 2 cannot produce at which point(s)?
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25. The point (0, 0) is the only critical point of the function f(,y)(2+y)++3 in the interior of the disk D +(+1 s 9/4). The following graph is of z .) restricted to the boundary of D, which is parameterized by -cost, y1n t, for 0s t s 2. Find the absolute minimum value of f(x, y) on D. (A) 0 (B) 2 (C) 3 25 3.25 (E) 2.9 (F) 3 (G) 3.25 (H) 4 25.. -8.25 (J) 9.25 3.75...
2. Second-order Butterworth CT and DT filters. (a) [5 pts] Given that He (s)- (s+e4(steJr/4 and that the corresponding fiter is causal, verify that He(0) 1. that Hc (jw) decreases monotonically with increasing positive values of u. that I He (j) | 2-1/2 (i.e., that wc-1 is the half-power frequency), and that (b) [3 pts] Give an expression for Hd(z), the bilinear transform applied to Hc(s) in part a. Choose T - 2 in the bilinear-transform formula, ie., (1- z1/(1z1)-(z...
Question 18 (1 point) Number of Workers 0 1 2 3 4 5 6 Number of Windows Produced Per Day 0 15 45 1290 135 165 180 The above table shows the total number of windows a window manufacture can produce each day if it hires a certain number of workers. What is the marginal product of the 5th worker? 165 windows per day 15 windows per day 30 windows per day 45 windows per day 29 A)