2)
We know,
Ksp = 1.8*10^-10
Given data,
[Ag+] = 0.1 M
[HCl] = 1 M
Let us consider a reaction,
Ag+(aq) + Cl-(aq) ---> AgCl(s)
There is a Cl- excess so , [Cl-] = 1.0 and Ag+ remains
We know that,
Ksp = [Ag+][Cl-]
1.8*10-10 = [Ag+](1.0)
Äg+* = (1.8*10^-10 ) / 1
[Ag+] = 1.8*10^-10 mol/L
2. Calculate the [Ag'] that would remain in solution under the conditions of the group precipita-...