#1. Null hypothesis : The average amount of caffeine in the house brewed blend of arabica is less than or equal to 75 mg
Alternate hypothesis: The average amount of caffeine in the house brewed blend of arabica is greater than 75 mg
#2. The type of test involved is "one-tailed right" since the region of rejection must fall under the upper tail to show the probability that the caffeine sampled falls greater than the amount claimed by the manufacturer.
#3. A Z test is used here since the population Range is known via which the population standard deviation can be found out. Also the sample size is greater than 30.
#4. The critical rejection region at 2.5% level of significance is 1.96 is also shown below
#5. Test statistic = Z = (Sample mean - mean under null hypothesis) / (standard deviation/sqrt(sample size))
Rule of thumb is standard deviation = range / 4 = 12/4 = 3
Z = (76 - 75) / (3/sqrt(36)) = 1/3 = 0.944
#6. The p-value corresponding to the test statistic = 0.173
#7. Since the pvalue is not greater than 0.025, we conclude that "we fail to reject the null hypothesis" i.e. "we fail to reject the claim that the amount of caffeine in the house brewed blend of arabica is less than or equal to 75 mg"
#8.
#9.
NAME: 1of 1 Solve the following problems and answer the following questions. Justify your solutio...
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