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Vapour pressure curves of HCN are described by following equations (p/Pa, T/K) hp= 26.396 In p- 22.725 -for liquid - gas equi

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Answer #1

If at all Solid gas euillibrium is considered at t=-180c18° c , the pressure will be

e(26.396-4293.9273-18)Pa according to the given equation, pressure=14145.85 Pa(26.396 273-18 Pa according to the given equation,pressure 14145.85 Pa for gas- solid equillibrium

Similarly according to the given equation in the question, pressure of liquid gas equilibrium =14827.16Pa.

Pressure given is 18kPa which is near to Liquid- gas equilibrium and as pressure is higher, definitely, HCN is in liquid state, because at higher pressure for the same temperature entropy of a substance will be less and therefore, a substance tend to be in liquid state.

According to clapeyron equation,

dPdT=∆HT*∆V, ∆V=Volume of vapour because, volume of vapor is≫>volume of liquid, i.e equation becomes dPdT= ∆HT*VVVV=volume of vapor=RT/P dP -Volume of vapour because, volume of vapor is >>> ΔΗ volume of liqid,l. e equation becomes avolume of vapor Vy-volume of v , classius clapeyron equation is valid here which is ln (P2/P1) = ∆HR*1T1-1T2, T1= -180C, here vapor pressure is R* (11- ) , T1- -18°C, here vapor pressure is14827.16Pa= P1, P2= 18000pa, here T2 is calculated by the equation given for vapour- liquid equilibrium in the question and we get the temperature as 258.826 K.

Latent heat of vaporisation = 27810.952213 J/mol

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