1) A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Use a 0.10 significance level for both parts. |
2) A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Use a 0.01 significance level for both parts. |
3) Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Use a 0.01 significance level for both parts. |
The test statistic, t, is
.
(Round to two decimal places as needed.)
The P-value is
.
(Round to three decimal places as needed.)
State the conclusion for the test.
A.
Fail to rejectFail to reject
the null hypothesis. There
isis
sufficient evidence to support the claim that men have a higher mean body temperature than women.
B.
RejectReject
the null hypothesis. There
is notis not
sufficient evidence to support the claim that men have a higher mean body temperature than women.
C.
RejectReject
the null hypothesis. There
isis
sufficient evidence to support the claim that men have a higher mean body temperature than women.
D.
Fail to rejectFail to reject
the null hypothesis. There
is notis not
sufficient evidence to support the claim that men have a higher mean body temperature than women.
b. Construct a confidence interval suitable for testing the claim that men have a higher mean body temperature than women.
less than<mu 1 minus mu 2μ1−μ2less than<
(Round to three decimal places as needed.)
Does the confidence interval support the conclusion of the test?
No,Yes,
because the confidence interval contains
2)
a)
Ho : µ1 - µ2 = 0
Ha : µ1-µ2 > 0
Level of Significance , α = 0.01
mean of sample 1, x̅1= 97.55
standard deviation of sample 1, s1 =
0.96
size of sample 1, n1= 11
mean of sample 2, x̅2= 97.41
standard deviation of sample 2, s2 =
0.65
size of sample 2, n2= 59
difference in sample means = x̅1-x̅2 =
0.1400
std error , SE = √(s1²/n1+s2²/n2) =
0.3016
t-statistic = ((x̅1-x̅2)-µd)/SE =
0.46
DF = min(n1-1 , n2-1 )= 10
p-value=0.326
p-value>α , Do not reject null hypothesis
Fail to reject
the null hypothesis. There
is not sufficient evidence to support the claim that men have a higher mean body temperature than women.
b)
t-critical value = t α/2 = 3.169 (excel formula
=t.inv(α/2,df)
std error , SE = √(s1²/n1+s2²/n2) =
0.3016
margin of error, E = t*SE =
0.9366 0.956
difference of means = x̅1-x̅2 =
0.1400
confidence interval is
Interval Lower Limit= (x̅1-x̅2) - E =
-0.816
Interval Upper Limit= (x̅1-x̅2) + E =
1.096
the confidence interval does not support the conclusion of the test
because the confidence interval contains 0 in th the interval
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