For tour vectors (1ab.d, (1.1,1,1), (1.2.3,1), (BA.5.3 (1,1,1,1 For four vectors (1,a,b,c), (1,1,...
Q6. Let W be the subspace of R' spanned by the vectors u. = 3(1, -1,1,1), uz = 5(–1,1,1,1). (a) Check that {uj,uz) is an orthonormal set using the dot product on R. (Hence it forms an orthonormal basis for W.) (b) Let w = (-1,1,5,5) EW. Using the formula in the box above, express was a linear combination of u and u. (c) Let v = (-1,1,3,5) = R'. Find the orthogonal projection of v onto W.
can anybody explain how to do #9 by using the theorem
2.7?
i know the vectors in those matrices are linearly independent,
span, and are bases, but i do not know how to show them with the
theorem 2.7
a matrix ever, the the col- ons of B. e rela- In Exercises 6-9, use Theorem 2.7 to determine which of the following sets of vectors are linearly independent, which span, and which are bases. 6. In R2t], bi = 1+t...
2) Given 3 vectors. 11 | u = 0 | u = -1 L2 a) What vector space do these vectors belong to? b) Geometrically describe the space spanned by vectors uj and u2. c) Is vector, v, in the subspace spanned by the vectors uj and u2? d) Are all 3 vectors linearly dependent or independent of each other? Explain why or why not. e) If possible, find the linear combination of vectors u; and uz that equals vector...
Problem 2 [2 4 6 81 Let A 1 3 0 5; L1 1 6 3 a) Find a basis for the nullspace of A b) Find the basis for the rowspace of A c) Find the basis for the range of A that consists of column vectors of A d) For each column vector which is not a basis vector that you obtained in c), express it as a linear combination of the basis vectors for the range of...
Problem 1: consider the set of vectors in R^3 of the
form:
Material on basis and dimension Problem 1: Consider the set of vectors in R' of the form < a-2b,b-a,5b> Prove that this set is a subspace of R' by showing closure under addition and scalar multiplication Find a basis for the subspace. Is the vector w-8,5,15> in the subspace? If so, express w as a linear combination of the basis vectors for the subspace. Give the dimension of...
2. For the following questions, you just need to circle one of answers. (1.5 points/each, totally 8 points) Let , be the set of all polynomials with exact degree 2. Is this a subspace of a,17(Yes b. Given 2 by 2 matrix A. S-(BeR 1AB BA) is a subspace of vector space R7 a. No) (Yes No) 1 AB-0), is S asubspace of 2 by 2 c. Given 2 by 2 matrix A. Let s- (Be R matrix vector space?...
Linear Algebra
6. (8pt) (a) Find a subset of the vectors v1 = (1, -1,5,2), V2 = (-2,3,1,0), V3 =(4,-5, 9,4), V4 = (0,4,2, -3) V5 = (-7, 18, 2, -8) that forms a basis for the space spanned by these vectors. (b) Use (a) to express each vector not in the basis as a linear combination of the basis vectors. (c) Let Vi V2 A= V3 V4 Use (a) to find the dimension of row(A), col(A), null(A), and of...
roblem 1: Consider the set of all vectors in R1 which are mutually orthogonal to the vectors <3,4,-1,1> and (a) The first thing you need to do is determine the form of all vectors in this space. Hints on how to proceed You need vectors < a,b,c,d> with the property that <a,b,c,d> is orthogonal to <3,4,-1,1>and <a,b,c,d is orthogonal to <1,1,0,2>. There's a vector equation that defines "orthogonal" and this will set up two equations. .That means you have two...
Please show work
Problem 2. Consider the vectors [1] 1 1 v1 = 1, V2 = -1, V3 = -3 , 04 = , 05 = 6 Let S CR5 be defined by S = span(V1, V2, V3, V4, 05). A. Find a basis for S. What is the dimension of S? B. For each of the vectors V1, V2, V3, V4.05 which is not in the basis, express that vector as linear combination of the basis vectors. C. Consider...
Please answer questions 2&3. Thank you!
Remember that: A subspace is never empty, and is either the just the zero vector. i.e. [0), or has an infinite number of vectors A basis for a subspace is a set of t vectors. where t is the dimension of the subspace (usually a small number.) These vectors span the subspace and are linearly independent. This means that 0 can never part of a basis. The basis of the subspace (0) is empty....