I need help with - What is the conclusion that can be drawn? - thank you!
As concrete cures, it gains strength. The following data represent the 7-day and 28-day strength in pounds per square inch (psi) of a certain type of concrete.
7-Day_Strength_(psi)_-_x
28-Day_Strength_(psi)_-_y
3390 5220
3340 4630
2300 4070
2480 4120
3380 5020
(a) Treating the 7-day strength as the explanatory variable, x, use technology to determine the estimates of β0 and β1.
β0≈b0= 1981.5
(Round to one decimal place as needed.)
β1≈b1= 0.8833
(Round to four decimal places as needed.)
(b) Compute the standard error of the estimate se.
se=230.5
(Round to one decimal place as needed.)
(c) A normal probability plot suggests that the residuals are normally distributed. Determine sb1. Use the answer from part (b).
sb1=0.2131
(Round to four decimal places as needed.)
(d) A normal probability plot suggests that the residuals are normally distributed. Test whether a linear relation exists between 7-day strength and 28-day strength at the α=0.05 level of significance. State the null and alternative hypotheses. Choose the correct answer below.
A.H0: β1=0 H1: β1>0
B. H0: β0=0 H1: β0≠0
C. H0: β1=0 H1: β1≠0 correct answer
D. H0: β0=0 H1: β0>0
Determine the P-value of this hypothesis test.
P-value =0.026
(Round to three decimal places as needed.)
What is the conclusion that can be drawn?
A.
Reject H0 and conclude that a linear relation exists between the 7-day and 28-day strength of a certain type of concrete at the α=0.05 level of significance.
B.
Do not reject H0 and conclude that a linear relation exists between the 7-day and 28-day strength of a certain type of concrete at the α=0.05level of significance.
C.
Reject H0 and conclude that a linear relation does not exist between the 7-day and 28-day strength of a certain type of concrete at the α=0.05 level of significance.
D.
Do not reject H0 and conclude that a linear relation does not exist between the 7-day and 28-day strength of a certain type of concrete at the α=0.05 level of significance.
Here null hypothesis H0 : 1 = 0
( linear relation does not exist between 7 day and 28 day strength of certain type of concrete)
Alternative hypothesis H1 : 1 0
( linear relation exists between 7 day and 28 day strength of certain type of concrete )
Test criteria : If p-value < we reject the null hypothesis H0 , otherwise we fail to reject the null hypothesis .
Here = 0.05
Our p value = 0.026 < 0.05
Conclusion : Reject H0 and conclude that a linear relation exists between the 7 day and 28 days strength of certain type of concrete at = 0.05 level if significance.
I need help with - What is the conclusion that can be drawn? - thank you! As concrete cures, it...
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