I just want the answer for part D. So, I will give the answers to the rest of the questions to assist in answering part d of the question.
A) i) 244.2 A (ii) 0.408 lagging (iii) 183.8 Nm B) (i) 0.033 (ii) 42.8A (iii) 5.7 (iv)0.941 lagging (v) 162.8 Nm (vi) 87% C) (i) Rth = 0.24 Xth = 0.49 X2 = 0.5 (ii) 0.196 (iii) 431.2 Nm
Hopefully, these answers will help
I just want the answer for part D. So, I will give the answers to the rest of the questions to as...
1) One phase equivalent parameter of a three-phase, 460V, 1740d / d, 60Hz, 4-pole, rotor wound asynchronous motor values are given below. R1 = 0.25Ω, R’2 = 0.2Ω, X1 = X’2 = 0.5Ω, Xm = 30Ω Rotary losses are 1700W. While the rotor terminal ends are short-circuited, find the following requirements. a) (i) Find the starting current when the motor is supplied with nominal voltage? (ii) Find the starting torque? b) (i) Find the slip at full load? (ii) Find...
A 3 phase, 460V, 60Hz, 6-pole induction motor has the following equivalent circuit parameters per phase: R1 = 0.2 ohms R2 = 0.28 ohms X1 = X2 = 1.055 ohms Xm = 33.9 ohms The no load losses, comprising friction, windage, and iron losses equal 26W. The motor is coupled to a load and connected to a 460V supply, and the rotor speed is found to be 1156 RPM. For this motor connected to a 460V supply calculate the following:...
Problem # 2: Induction Motor Analysis Using The Thevenin Theorem [37 points] A three-phase, two pole, 25hp, 460V (line-line), 60Hz, wye-connected, squirrel-cage induction motor has the following per-phase parameters: Ri 0.53 Ohm X2 0.80 Ohm Xi 1.80 Ohms R2 0.30 Ohm Re- 400 Ohms Xm 25.0 Ohms You cannot use any approximate circ uit or any approximation in the calculations. (1) Determine the parameters of the Thevenin equivalent circuit. Draw the equivalent circuit with the appropriate parameter values indicated on...
. A three-phase, 460V, 60Hz, 4 – pole Y – connected induction motor has the following equivalent circuit parameters: Rs = 0.42Ω, Rr ′ = 0.23Ω, Xs = Xr ′ =0.82Ω, and Xm = 22Ω. The no load loss Ploss = 60W, assumed as a constant. The rotor speed is 1750 rpm.Use the approximate equivalent circuit ( i.e. the Xm branch is at the very left of the circuit) determine the followinga. the synchronous speedb. the slip sc. the input...
A 3-phase, 460 V, 1740 rpm, 60 Hz, 4-pole wound-rotor induction motor has the following parameters per phase: R1 = 0.25 Ω, ' 2R = 0.2Ω, ' 1 2 X = X = 0.5Ω, 30 m X = Ω. The rotational losses are 1700 W. With the rotor terminals short-circuited, find: 1. at starting: • current when started direct on full voltage, • a torque 2. at full load: • slip • current • ratio of starting current to full-load...
Please use exact methods and not approximations! 7.15. A three-phase, 460 V, 60 Hz, 1760 rpm, wound-rotor induction motor has the following equivalent circuit parameters Ri=0.25 ohm : R'= 0.2 ohm : Xi = 1.2 ohm : X2,= 1.1 ohm : 'Ku = 35 ohm The motor is connected to a 3ph, 460V, 60Hz supply and is star-connected. Use the simplified equivalent circuit. Initially the external rotor resistance is set to zero. (a) Calculate the speed (in rpm) at which...
4.6. A 460-V, 75 kW, 4-pole, delta-connected, 60-Hz, three- phase induction motor has a full-load slip of 5 percent, an efficiency of 92 percent and a power-factor of 0.87 lagging at full-load. At start-up, the motor develops 1.9 times the full load developed torque but draws 7.5 times the rated current at the rated voltage. This motor is to be started with an auto- transformer reduced-voltage starter. Assume the stator resistance and the stator core loss to be negligible. Calculate...
4. A certain four-pole 240-V-rms 50-Hz delta-connected three-phase induction motor operates at slip 5% at full load and has rotational losses (windage + friction) of 100 W. The stator resistance per phase is 0.2 Ohm. The results of no-load and locked-rotor tests on this motor are as follows: No-load test Locked-rotor test Line-to-line input voltage: 240 V 45 V Input active power: 1100 W 1300 W Input line current: 10 A 30 A Using the tests data, determine parameters of...
5. A 208-V four-pole 60-Hz Y-connected wound-rotor induction motor is rated at 30 hp. Its equivalent circuit components are R=0.100 Ry=0.070. X - 10.00 R = 250 X; -0.2100 X=0.21002 Praw=500 W P =0.5% of input at full load For a slip of 0.05, find (a) The line current (b) The induced voltage in the rotor (c) The stator power factor (d) The rotor power factor (e) The rotor frequency (f) The stator copper losses (g) The core loss (h)...
Question 2 (10 marks) (a) A large 3-phase, 4000 V, 60 Hz, slip of 0.01, squirrel cage induction motor draws a current of 375 A and a total active power of 2300 kW when operating at full-load. The stator is connected in wye and the resistance per phase is 0.05 12. The total iron losses are 23 kW and the windage and friction losses are 10 kW. Calculate the following: i) The power factor at full-load ii) The active power...