Answer 5:
If non disjunction at meiosis one then two gametes carry two copies of chromosomes and two gametes are empty.
If non disjunction occur at meiosis two, then two normal gametes and one gamete with two copies of chromosomes and one gamete is empty.
Answer 6: first child has trisomy A aa. This child has a allele contributed from the father, because mother lack this allele. Mother is homozygous for A allele. So mother contributed A allele in first child. Now a allele contributed from father. This a allele is non disjunction at meiosis two stage. If non disjunction occur at meiosis one, then the child received Aa allele from the father. The genotype of child will be AAa.
First child genotype:AAa is example of aneuploidy trisomy. Aneuploidy: abnormal chromosome number.
Trisomy: person have three chromosome instead of two copies.
5. A man homozygous for a rare recessive disorder (a/a) marries a normal woman (A/A) If nondisjun...
4. A man makes 0 units of an enzyme due to homozygous recessive gene on chromosome 21. He marries a woman who produces 100 units of the same enzyme due to the heterozygous pairs of genes on her chromosomes 21. Their firstborn son has three copies of chromosome 21 and produces 200 units of the enzyme mentioned above. a) In which parent did the nondisjunction occur? b) Did the nondisjunction occur in meiosis I, meiosis II or mitosis? c) What...
4. A man makes 0 units of an enzyme due to homozygous recessive gene on chromosome 21. He marries a woman who produces 100 units of the same enzyme due to the heterozygous pairs of genes on her chromosomes 21. Their firstborn son has three copies of chromosome 21 and produces 200 units of the enzyme mentioned above. a) In which parent did the nondisjunction occur? b) Did the nondisjunction occur in meiosis I, meiosis II or mitosis? c) What...
A woman marries a man with two rare, recessive X-linked alleles, a and b. Their daughter marries a normal man. What will the phenotypes of their female children be?
Hemophilia is a sex-linked X-linked recessive trait. A homozygous normal woman marries a normal man whose brother has hemophilia. What are the chances of them having a hemophiliac son; hemophiliac daughter?
A woman who is heterozygous for normal vision marries a man with normal vision. If they have a girl, what is the probability she is colorblind? And what if it is a boy?
7. A colorblind woman and a man with normal vision have a son with Klineflter syndrome (XXY) who has normal vision. Determine the parent in whom nondisjuction occurs, and whether nondisjuction takes place in the first of second meiotic division. Colorblindness is an X-linked recessive trait. a. female meiosis I b. Either male meiosis I or II. c. male meiosis II d. female meiosis II e. male meiosis I
31. A polydactylous woman, otherwise normal, marries a healthy normal man. Their four children have the following phenotypes: (6 pt) Child 1 is normal in all respects; Child 3 has cystic fibrosis, otherwise normal Child 2 is polydactylous, otherwise normal; Child 4 has cystic fibrosis and is polydactylous. A. What is the genotype of the mother? B. What is the genotype of child 3? C. What is the genotype of child 4? D. What is the chance that child 1...
Colorblindness is a sex-linked X-linked recessive trait. A normal woman marries a color-blind man. They have a color-blind daughter. What are the genotypes of all three people?
A colorblind woman marries a man who is not colorblind. What is the phenotypic ratio of the offspring? In humans, freckles are dominant over absence of freckles, and curly hair is incompletely dominant with straight hair. A freckled, wavy-haired woman has kids with a freckled straight-haired man. Both the man and woman have one homozygous dominant parent and one homozygous recessive parent for freckles. What is the phenotypic ratio of the man and woman’s kids? Pigment in the mouse is...
Two normal parents have a daughter with hemophilia (an X-linked recessive disorder) that also has Turner Syndrome. a. Write out the cross as described above illustrating the genotypes and phenotypes of the parents and child. b. Did the non-disjunction event occur in the mother, the father, or could have occurred in either of the two parents? Did the nondisjunction event occur during meiosis I, meiosis II, or could it have occurred in either division during meiosis.