You use the binomial distribution.
P(x) = C(n,x)p^x(1-p)^(n-x) As p = 1/2, 1-p = 1/2 also, so p^x(1-p)^(n-x) = 1/2^x*1/2^(n-x) = 1/2^n
Thus, as n = 5
Thus, P(x) = C(5,x)(1/2)^5 = C(5,x)/2^5 = C(5,x)/32
Then, P(2) = C(5,2)/32 = 5*4/(2*1)/32 = (20/2)/32 = 10/32 = 5/16
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