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18, + 03 points i Frenous Answars The shortest pipein a particular organ is 1.41 m (a) Determine the frequency (in Hz) of the

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Answer #1

a) 9th harmonic,

f9 = 9*v/(4*L)

= 9*331.6/(4*1.41)

= 529.1 Hz

b) f9 = 9*v/(2*L)

= 9*331.6/(2*1.41)

= 1058 Hz

c) at T = 20 C

v = 331.6 + 20*0.6

= 343.6 m/s

for closed pipe,
f9 = 9*v/(4*L)

= 9*343.6/(4*1.41)

= 548.3 Hz

for open pipe,
f9 = 9*v/(2*L)

= 9*343.6/(2*1.41)

= 1096 Hz

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18, + 03 points i Frenous Answars The shortest pipein a particular organ is 1.41 m (a) Determine the frequency (in Hz) of the ninth harmonic (at 0°C) if the pipe is closed at one end. 548.93 Racall t...
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