Ans:
a)N=21+16+148
df(type)=3-1=2
df(residual)=48-3=45
SS(residual)=45*56.7=2551.5
MS(type)=754.4/2=377.2
F=MS(type)/MS(residual)=377.2/56.7=6.65
Source | df | SS | MS | F |
type | 2 | 754.4 | 377.2 | 6.65 |
residuals | 45 | 2551.5 | 56.7 | |
total | 47 | 3305.9 |
b)
=MS(residual)=56.7
c)SS(total)=754.4+2551.5=3305.9
d)F=6.65
p-value=FDIST(6.65,2,45)=0.0029
As,p-value<0.05,we reject the null hypothesis.
There is sufficient evidence to conclude that there is significant difference among the types.
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