Question

genetics problem. need help with both questions and drawings are helpful. thank u.

Question 11) (7 points) Consider 10 genes on different chromosomes in a diploid organism. An individual is homozygous for 6 genes and heterozygous for 4 genes. Among a large population of gametes from that individual, how many different genotypes do you predict would be present? Question 12) (6 points) There are several genes in humans in addition to the I gene (for ABO blood group) that generate antigens on red blood cells. Two examples are the MN gene and the Rh gene. M and N are codominant alleles. The R allele is dominant to the r allele A mother has phenotype A N R Her child has phenotype AB MN R Which genotype below could be the father? a) IA/i M/N r/r b) B/i M/N r/r c) i/i N/N r/r d) IB/i N/N R/R e) I/IA M/N R/R

Answer 1

Answer 11 if a person is homozygous for 6 gene and heterozygous for 4 gene then the possibility of having homozygous gene in gamete will be 1 but for heterozygous it becomes 1/2. So accordingly for 4 gene the possiblility of gametes combination is 2ⁿ where n is number of genes

So there are four gene the possibility becomes = 2⁴ = 16 types of gametes from heterozygous and from homozygous is 1 then in total there will be 16 different genotype of gametes.

Answer 12 So from given data we can see that child blood is AB MN R, and mother ghenotype is A N R, So it means that father must have B type then in MN type father must have M type, also the R type can be R or r

So only B show the desired phenotype of father i.e i^B/i M/N r/r