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Use the following information to answer questions6 to 9 Tomato Plant Leaves In tomatoes, regular leaves (L-) are multilobed a
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a. Data set 1 is from a smal sample size and data set 2 is from a large sample size. hat you see in how different the observe
Use the following information to answer questions6 to 9 Tomato Plant Leaves In tomatoes, regular leaves (L-) are multilobed and serrated and potato leaves ( are smooth, and single 0mage 1). Red fruit °F) is dominant to yellow fruit image 1. Potato leaves (ett) and regular leaves rigng A cross is carried out between two pure lines of tomato plants, one having regular leaves and red fruit and the other having potato leaves and yellow fruit. The F, generation all have regular leaves and red fruit. The F, Individuals are then crossed with one another Complete a Punnett square to determine the expected F, progeny on the basis of Mendel's Law of Independent Assortment, which states that the alleles for one gene segregate independently of the alleles for other genes during gamete formation. 6. L-duninast recesv


a. Data set 1 is from a smal sample size and data set 2 is from a large sample size. hat you see in how different the observed results are from the expected results between the two data sets. Compare each da ta set to the expected probabilities. Explain any differences O 0b. Compare the expected probabilities of each phenotypic class to the observed Compare the axpected probabilties f ach phenotypic class to the observed probabilies for data set 2 dlarge sample size) to determine if the genes for leaf shape and fruit colour assort independently
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Answer #1

6) FfLl*FfLl

FL Fl fL fl
FL FFLL (regular red) FFLl (regular red) FfLL (regular red) FfLl (regular red)
Fl FFLl (regular red) FFll ( potato, red) FfLl (regular red) Ffll ( potato, red)
fL FfLL (regular red) FfLl (regular red) ffLL ( yellow,regular) ffLl ( yellow,regular)
fl FfLl (regular red) Ffll ( potato, red) ffLl ( yellow,regular) ffll ( yellow, potato)

7) regular red=9

potato, red = 3

regular yellow=3

potato, yellow= 1

so phenotypic ratio

regular red: potato red: regular yellow: potato yellow=9:3:3:1

8) i) expected phenotypic ratio is

regular red: potato red: regular yellow: potato yellow=9:3:3:1

expected probabilities

probability of regular red= number of the regular red/ total number

=9/16

probability of potato red= number of potato leaves, red fruit/total number

=3/16

probability of regular yellow= number of regular leaves and yellow fruits/total number

=3/16

probability of potato, yellow= number of potato yellow/ total number

=1/16

Phenotype Expected probabilities Data set 1 Data set 2
Regular, red 9/16=0.5625 26/59=0.4407 846/1500=0.564
Regular, yellow 3/16=0.1875 15/59=0.254 273/1500=0.182
potato, red 3/16=0.1875 6/59=0.102 287/1500=01913
potato, yellow 1/16=0.0625 12/59=0.2034 94/1500=0.0627
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