Question

Question 1 Figure shows the longitudinal section of proposed road with formation width of 12 m which is rise at a slope if 1 :300. The side slope are to be 1 in 1 for cut and 1 in 2 for fill. At chainage 40, the reduce level for proposed road is remain as existing reduce level. By considering the existing ground surface is horizontal, Calculate the 1. Volume material to be fill 2. Volume material to be cut 9SSL

Answer 1

Give n Side slope in cut. (S)ㄷ 1. Side stopa 'n al graan en chn lenyt , Change maion le H rem ha at chainage yo, formab on level coin cides with the arouna lenel RL of around lend Rey mahon level F968. Now At chainag le ss hm 4o formaktiom level ul be leuer hm689 ishich can be abtained dednch eser For enample For mohon level at chane 39 9684- o.1 9.589 w. chain age 20 = 9,685-04x(40-20) manon Le rel a or o

689 m. Simi Lar At ch be. higher than annage more for m ahmlenefwiU, han 40 t shich can be obbaineA pey choin Lwnth ajts chinage

Chainage	0	20	40	70	95	115
Ground level (GL)	9.772	10.234	9.689	9.587	9.611	9.776
Formation level (FL)	5.689	7.689	9.689	12.689	15.189	17.189
Depth (or level difference) = FL - GL	-4.083	-2.545	0.000	3.102	5.578	7.413

[Note: Negative depth indicates cutting. Positive depth indicates filling]

Chainage	Length (L) (in m)	Depth (h)		Mean depth (d)	B * d	S * d2	A = BD + Sd2	Volume (V) = A * L
B = 12 m,                         S1 (cutting) = 1,                            S2 (filling) = 2								Cutting	Filling
0		-4.083	Cutting
	(20-0)*30 = 600			(-4.083-2.545)/2 = - 3.314	39.768	10.983	50.751	30450.3576
20		-2.545
	600			-1.273	16.549	1.621	18.170	10901.7174
40		0
	900		Filling	1.551	18.612	4.811	23.423		21080.8818
70		3.102
	750			4.340	52.080	37.671	89.751		67313.4
95		5.578
	600			6.496	77.952	84.383	162.335		97401.0243
115		7.413
Total volume								41352.075	185795.3061

[Note: In the above table, while finding the value of (B * h), ignore the negative sign of 'h'. Because sign of 'h' just indicates whether it is cutting or filling and the same is considered in the last column]

Total volume of cutting = 41352.075 m³  

Total volume of filling = 185795.3061 m³