Question

Two population prportions CI Find the confidence interval for the difference between two population proportions. 3) 3) A researcher finds that of 1000 people who said that they attend a religious service at least once a week, 31 stopped to help a person with car trouble. Of 1200 people interviewed who had not attended a religious service at least once a month, 22 stopped to help a person with car trouble. Use 95 percent confidence to construct the confidence interval for the difference between two population proportions....。n- o.DIP Make a clear conclusion about the difference between two population proportions in the context of the story What can you conclude about an influence of an attendance of a religious service on people behavior when it comes to help a person with car trouble

Answer 1

3)

We need to construct the 95% confidence interval for the difference between population proportions P P2. We have been provided with the following information about the sample proportions: Favorable Cases 1 (X) Sample Size 1 (Ni) Favorable Cases 2 (X2)- Sample Size 2 (N2) 31 1000 1200 The sample proportion 1 is computed as follows, based on the sample size N number of favorable cases X1 -31: 1000 and the X 31 Pi 10000.031 The sample proportion 2 is computed as follows, based on the sample size N2 number of favorable cases X2 22: 1200 and the 4222 12000.018 The critical value for α-0.05 is ze-Z1-a/2-1.96. The corresponding confidence interval is computed as shown below

N2 0.031(1-0.031)0.018(1 0.018) V-T000 0,031 -0018+1.96x 0.0311-0.031)+08(1-0.018) | 0.031-0.018-1.96 x = 1)0 1200 1000

= ( - 0.0001 , 0.0261 )

Since the 95 % confidence interval includes value 0 , we can say that there is no significant difference between the two population proportions.

Hence, we can conclude that there is no influence of an attendance of a religious service on people behavior when it comes to help a person with car trouble.