Question

A student took 5.03 mL 0.200 M Fe(NO3)3 solution, added 25.18 mL of DI water, mixed the resulting solution thoroughly and placed the solution in a 50 mL buret. Then, the student took 10.09 mL of this...

A student took 5.03 mL 0.200 M Fe(NO3)3 solution, added 25.18 mL of DI water, mixed the resulting solution thoroughly and placed the solution in a 50 mL buret. Then, the student took 10.09 mL of this dilute solution from the buret and mixed it thoroughly with 6.21 mL 0.00200 M NH4SCN and 28.65 mL DI water to form the reaction system. What are the initial [Fe3+] and the initial [SCN-] in this reaction system?

( ) [Fe3+]Initial = 7.47 x 10-3 M and [SCN-]Initial = 2.76 x 10-4 M

( ) [Fe3+]Initial = 0.200 M and [SCN-]Initial = 0.00200 M

( ) [Fe3+]Initial = 3.33 x 10-2 M and [SCN-]Initial = 2.76 x 10-4 M

( ) [Fe3+]Initial = 1.01 x 10-3 M and [SCN-]Initial = 1.24 x 10-5 M

0 0
Add a comment Improve this question Transcribed image text
Answer #1

1.006 nulli. mok oo 033 mo 60.00 2 44-98 0

Add a comment
Know the answer?
Add Answer to:
A student took 5.03 mL 0.200 M Fe(NO3)3 solution, added 25.18 mL of DI water, mixed the resulting solution thoroughly and placed the solution in a 50 mL buret. Then, the student took 10.09 mL of this...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A 25.0 mL volume of 0.0200 M Fe(NO3)3 is mixed with 50.0 mL of 0.00200 M...

    A 25.0 mL volume of 0.0200 M Fe(NO3)3 is mixed with 50.0 mL of 0.00200 M NaSCN and 25.0 mL of 0.100 HNO3. The blood-red FeSCN2+ ion forms and the equilibrium is established: Fe3+(aq) + SCN-(aq) <---> FeSCN2+(aq) The equilibrium concentration of FeSCN2+ ([FeSCN2+]) was measured spectrophotometrically and found to be 7.0 x 10-4 mol/L. To calculate the equilibrium constant (Kc) for thr equilibrium system, proceed through the following steps: A. Moles of Fe3+, initial B. Moles of SCN-, initial...

  • 4.81 mL of 0.00200 M Fe(NO3)3, 2.85 mL of 0.00200 M KSCN and 2.34 mL of...

    4.81 mL of 0.00200 M Fe(NO3)3, 2.85 mL of 0.00200 M KSCN and 2.34 mL of distilled water were mixed. The resulting solution was allowed to attain equilibrium at 24 oC. The absorbance of the equilibrium solution was recorded, and the [FeSCN2+] was determined graphically to be 7.58 x 10-5 M. Part A: Calculate the number of moles of Fe3+ initially added to the solution. Part B: Calculate the number of moles of FeSCN2+ formed in the solution at equilibrium....

  • A student mixes 5.12 mL of 4.02 x 10 M Fe(NO3)3 with 4.88 mL 2.01 x...

    A student mixes 5.12 mL of 4.02 x 10 M Fe(NO3)3 with 4.88 mL 2.01 x 103 M KSCN. She finds that in the equilibrium mixture the concentration of FeSCN2 is 1.40 x 10 M. 1. What is the initial concentration in solution of the Fe3 and SCN'? What is the equilibrium constant for the reaction? What happened to the K' and the NO3 ions in this solution? a. b. C. A student mixes 5.12 mL of 4.02 x 10...

  • Consider the following: A student mixes 5.00 mL 2.00 × 10−3 M Fe(NO3)3 with 3.00 mL...

    Consider the following: A student mixes 5.00 mL 2.00 × 10−3 M Fe(NO3)3 with 3.00 mL 2.00 × 10−3 M KSCN. She finds that in the equilibrium mixture the concentration of FeSCN2+ is 1.28 × 10−4 M. Find Kc for the reaction Fe3+(aq) + SCN−(aq) ↔ FeSCN2+(aq). a. What is the initial concentration of Fe3+ in the reaction mixture? [Fe3+] = ___ x 10-3 M b. What is the initial concentration of SCN- in the reaction mixture? [SCN-] = ___...

  • 4. When 5.00 mL of 0.500 M Fe (NO3)3 are mixed with 5.00 mL of 0.250...

    4. When 5.00 mL of 0.500 M Fe (NO3)3 are mixed with 5.00 mL of 0.250 M NaSCN, the following reaction occurs: Fe3+ (aq) + SCN(aq) $ FeSCN2+(aq) At equilibrium the concentration of FeSCN2- is found to be 6.00 x 10-2 M. A. Fill in the table below with the proper numerical values. (Remember to take into account the effects of dilution when calculating the initial molarity of Fe3+ (aq) and SCN'(aq) Fes- (aq) SCN (aq) FeSCN-(aq) Initial Molarity Change...

  • a. A 10 ml calibration solution is made by mixing 5 mL of 0.200 M Fe(NO3)3,...

    a. A 10 ml calibration solution is made by mixing 5 mL of 0.200 M Fe(NO3)3, 1.50 mL of 2.00X10-3 M KNCS, 1 mL of 0.100 M nitric acid and 2.50 mL H20. What is the final concentration of only the NCS-ion? b. If 1.00 ml of this solution is then diluted to a final volume of 25.00 ml with DI water. What is the new concentration of NCS?

  • A student mixes 5.00 mL 4.00 x 10-3 M Fe(NO3)3 with 5.00 mL 4.00 x 10-3 M KSCN.

    A student mixes 5.00 mL 4.00 x 10-3 M Fe(NO3)3 with 5.00 mL 4.00 x 10-3 M KSCN. The student finds that the equilibrium concentration of FeSCN2+ is 5.6 x 10-4M. a. Set up the Kc expression for the following equation. Fe3+ + SCN-  ↔ FeSCN2+b. What is the total volume of the solution? _______ mL c. Fill in the following table for the moles of each species.d. Find the concentration for the above ions. e. Calculate Kc for the reaction.

  • A student mixed 4.00 mL of 1.02 x 10-1 M Fe(O3)3 with 100.0 mL of 1.98...

    A student mixed 4.00 mL of 1.02 x 10-1 M Fe(O3)3 with 100.0 mL of 1.98 x 10-4 M KSCN using 5.0 x 10-1 M HNO3 as the solvent for both solutions and found the absorbance of the resulting equilibrium mixture to be 0.235. Given these data, calculate the K value (The e value for Fe(SCN)2+ is 4700 L mole-1cm-1 and b = 1 cm) I got: [Fe^3+] = 3.87 x 10^-3 M [SCN^-] = 1.40 x 10^-4 M [Fe(SCN)^2+]...

  • A mixture is prepared by combining 10.20 mL of 1.80 x 10-3 M Fe(NO3)3 with 10.00...

    A mixture is prepared by combining 10.20 mL of 1.80 x 10-3 M Fe(NO3)3 with 10.00 mL of 1.68 x 10-3 M KSCN. The solution turns red due to the formation of FeSCN2+. The absorbance is measured and, using a calibration plot, the [FeSCN2+] at equilibrium is found to be 2.20 x 10-4 M. Complete the following ICE table Fe3+   + SCN-     ⇌ FeSCN2+ initial (M) (A) (B) (C) change (M) (D) (E) (F) equilibrium (M) (G) (H) (I) What...

  • 1. A student mixes 5.00 mL of 2.00 x 10 M Fe(NO3)3 with 5.0 mL of...

    1. A student mixes 5.00 mL of 2.00 x 10 M Fe(NO3)3 with 5.0 mL of 2.00 x 10-3 M KSCN. She finds that in the equilibrium mixture the concentration of FeSCN+2 is 1.2 x 104 M. Find the Kc for the reaction of Fe (aq) + SCN (aq) → FeSCN2(aq) using the following steps. a. Find the initial concentration of Fe and SCN. (Use Equation 4). Record the value in the ICE Chart below. b. What is the equilibrium...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT