Question

Name: Lab Partner(s) Date: Question What would be the density of lab gas at STP (o C and i atm)? (Hints (You do NOT have to answer these questions in italics; they are only here to help you answer the actual question.): There are TONS of different ways to approach this problem. If you were to bring your sample of lab gas to STP, what (from the ideal gas equation) would change? How would you expect this change to affect your density? Can you use a gas law to áccount for the change? What if, instead, you performed the same experiment in an environment of STP, what would change about your measurements? Is there an easy way to account for this? To help think about the problem, draw a picture if you need to.) wwesto 3 deciomal ty a What is the probalbility that a hospital employee will report hourn motation, show your calculation set up,give our result in decimal form. 2 points) What is the probability that an employee reporting day shift? Give the probability notation, show your calculation set up. form. (2 points) b. 5-5.s hours of sleep will be someone on the your result in decimal c. What is P(E |4-43)? Write it out in words, show your calculation set up. result in your calculation set up. give your decimal form. (2 points d. Which is bigger, P(6-6.5 I E) or P(6-6.5 | N)? Show your calculation set ups, give your results in decimal form. Interpret your result in words for this specific problem. (2 points) e Based on this survey, what is the 95% confidence interval for P(7-75)? Give your calcul command. Interpret your confidence interval in the context of this problem. (2 points)

Answer 1

3a. Probability that a hospital employee will report 8 hours of sleep - P(8) 7/(9+24 +26 +26 + 7) 0.076 (rounded 3 decimal places) b. Probability that an employee reporting 5-5.5 hours of sleep will be someone on the day shift P(D5-5.5)-11/24-0458 (rounded 3 decimal places) c. P(E4 4.5) 5/9 0.556 d. P(6 6.5E) 10/(5+7+10+8+4) 0.294 P(6-6.5| N) = 10/(4-6 +104 11 + 1) 0.313 P(6 6.5E) < P(6- 6.5IN) e. P(7-75) = 26/(94 24-264 264 7) = 0.283 = ê, say 95% CI. for P(7-75) is (1-2) = (0.191, 0.375) 20,025 × 0.025 × where, n-9 + 24 + 26 + 26 + 7 92, Żo025 1.06