Question

EE Phasor Homework help?:

Phasor Homework help?

1a) Design two different circuits, each with an AC voltage source and at least one resistor, one inductor and one capacitor. You can make these as simple or as complicated as you want. For each circuit, calculate the phasor voltage (magnitude and angle) across each component. Assume the source has a phase angle of 0^o. Note: this is at a single fixed frequency of your choice. You can either use the same frequency for both circuits, or different ones.

1b) Simulate your circuits in LTSpice and verify your calculations.

Answer 1

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Edit Simulation Command Transient AC Analysis DC sweep Noise DC Transfer DC op pnt Compute the small signal AC behavior of the circuit lineanized about its DC operating point Type of sweepinear Number of points: Start frequency: 159.155 Stop frequency:59.155 Syntax: ac <oct, dec, lin> <Npoints> <StartFreq> <EndFreq> ac lin 1 159.155 159.155 OK Cancel A.C sweep simulation settings using LT-SPICE

*C\Users vaibhav Desktop\Draft1.asc -AC Analysis - frequency 159.15!5 Hz R1 L1 0.970137 phase: 1 phase 1.21267 phase -14.0362 mag: Vc 2 mag: -14.0376 75.9624° (vc): mag: mag: 0.0242534 phase: V1 C1 10m I (C1) I (Ll) I (R1) I (V1) 10 mag: 0.0242534 phase: 75.9624° -104.038 -104.038 mag: 0.0242534 phase: 20μ mag: 0.0242534 phase SINE(0 1 159.155 0 0 0) AC 1 VRI-V(1)-V(2) =0.242< 75.96" volt VL1- V(2)- V(vc)-0.242 < 165.96 volt V(C1)- V(vc)1.2126 <-14.036 volt .ac lin 1 159.155 159.155 Circuit simulation using LT-SPICE obtained results

IH 2L 4J 9-0 4L 0.3123 /-128-6S9 Amprre onnd

o, olryp avross 0.3/23 -,29,659 voir QX n time domain eapreisim Va사 28.659 vt Answer We can verify all the answers using LT-SPICE Simulation-

47 Edit Simulation Command Transient AC Analysis DC sweep Noise DC Transfer DC op prt Compute the small signal AC behavior of the circuit lineanized about its DC operating point. Type of sweep: Linear Number of points: Start frequency 1.5915 Stop frequency: 1.5915 Syntax: ac <oct, dec, lin> <Npoints> <StartFreq> <EndFreq> ac lin 1 1.5915 1.5915 Cancel OK A.C sweep settings using LTSPICE

CUsers vaibha Desktop Draft3.asc AC Analysis L1 1.5915 frequency: V11 4 phase: 7.95139e-016° mag: mag 0.624718 phase -128. 652 V (2): R1 C1 0.31234y phase: -38.652 mag 0.05 I (L1): I (R1) 2 mag 0.441736 phase: 83.6531° SINE(0 4 1.5915 0 0 0) AC 4 0.312359 phase: mag: 1 (VI) : 96.3469° mag:0.441736 phase: .ac lin 1 1.5915 1.5915 V(R1)-V(C1)- V(2)-0.6247<-128.652 volt V(LI)-V(1)-V(2)-4.41<6.341° volt Circuit simulation using LT-SPICE Obtained results Exactly matches with calculation