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Air with a stagnation pressure of 1000 kPa and stagnation temperature of 500 K flows isentropically into a 100 kPA ambient (back) pressure. Calculate the Area ratio at the exit of a nozzle for isentro...

Air with a stagnation pressure of 1000 kPa and stagnation temperature of 500 K flows isentropically into a 100 kPA ambient (back) pressure. Calculate the Area ratio at the exit of a nozzle for isentropic flow with these conditions. Further if flow is considered isentropic within the nozzle calculate the isentropic nozzle efficiency if the area ratio at the nozzle exit were 1.2 rather than your calculated value for isentropic exit conditions above.

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loo0O - 100 looo tables of qir Po o218 556-6815 500 es 258.5q k 어-01278 J-1.6875 2-0050 6815 O031218 = 1.945

Avea ratio- 1.2 At 0 1-2502o 66ly 1-2-1114 1、2502-н ч o 6825 500 ho-he ho-hes 500-84-21 500 - 258.8q - 0-65 T5 s* 65.75

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